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ziro4ka [17]
2 years ago
7

What's an algorithm ?​

Mathematics
2 answers:
mylen [45]2 years ago
8 0

Any series of well defined steps that shows a procedure for solving a given type of problem is called an algorithm.

Step-by-step explanation:

<h3>Hope it helps you !!</h3>
Charra [1.4K]2 years ago
5 0

Answer:An algorithm is a set of instructions for solving a problem or accomplishing a task.

Step-by-step explanation:

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A frightened child is restrained by her mother as the child slides down a frictionless playground slide. If the force on the chi
MissTica

Answer:

Step-by-step explanation:

Given

Restrained Force F=116 N

Increase in Kinetic Energy \Delta K.E.=30 J

Distance moved d=1.9 m

Work done by all the forces is equal to change in Kinetic Energy of Object i.e. by gravity force, Normal force and Applied Force

\Delta K.E.=W_g+W_f+W_N

30=W_g-F\cdot d

30=W_g-116\cdot 1.9

W_g=250.4 J

(b)In absence of applied force thus

work done by gravity will be equal to  change in kinetic Energy

change in Kinetic Energy=210 J

6 0
3 years ago
NO LINKS OR FILES!
Archy [21]

(a) If the particle's position (measured with some unit) at time <em>t</em> is given by <em>s(t)</em>, where

s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}

then the velocity at time <em>t</em>, <em>v(t)</em>, is given by the derivative of <em>s(t)</em>,

v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}

(b) The velocity after 3 seconds is

v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}

(c) The particle is at rest when its velocity is zero:

\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|

In interval notation, this happens for <em>t</em> in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

\displaystyle \int_0^8 |v(t)|\,\mathrm dt

By definition of absolute value, we have

|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)

In part (d), we've shown that <em>v(t)</em> > 0 when -√11 < <em>t</em> < √11, so we split up the integral at <em>t</em> = √11 as

\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt

and by the fundamental theorem of calculus, since we know <em>v(t)</em> is the derivative of <em>s(t)</em>, this reduces to

s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}

7 0
2 years ago
What is 7 divided by 1/9
MakcuM [25]
The answer 0.777777777
8 0
3 years ago
Read 2 more answers
2×3+4-5 <br>please help ​
Andru [333]

Step-by-step explanation:

PEMDAS

parentheses, exponents, multiplication, division, addition, subtraction.

first multiply:

2×3=6

6+4-5

Now add

6+4=10

Now subtract

10-5=5

5 is the answer

<em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helped</u></em><em><u>!</u></em><em><u> </u></em><em><u>:</u></em><em><u>)</u></em>

8 0
3 years ago
Read 2 more answers
Answer ASAP and both questions :D
dangina [55]

the student needed to place a ten outside the radical, as a perfect square of 100 composes 200. This way, a two should be left under the radical sign. Also, this would be about 14.1 because 14^2 is 196 and 15^2 is 225. The correct answer must be less than 225, more than 196, but closer to 196. Therefore, a .1 is added to the 14

4 0
3 years ago
Read 2 more answers
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