Answer:
Step-by-step explanation:
Given
Restrained Force 
Increase in Kinetic Energy 
Distance moved d=1.9 m
Work done by all the forces is equal to change in Kinetic Energy of Object i.e. by gravity force, Normal force and Applied Force




(b)In absence of applied force thus
work done by gravity will be equal to change in kinetic Energy
change in Kinetic Energy
(a) If the particle's position (measured with some unit) at time <em>t</em> is given by <em>s(t)</em>, where

then the velocity at time <em>t</em>, <em>v(t)</em>, is given by the derivative of <em>s(t)</em>,

(b) The velocity after 3 seconds is

(c) The particle is at rest when its velocity is zero:

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

In interval notation, this happens for <em>t</em> in the interval (0, √11) or approximately (0, 3.317) s.
(e) The total distance traveled is given by the definite integral,

By definition of absolute value, we have

In part (d), we've shown that <em>v(t)</em> > 0 when -√11 < <em>t</em> < √11, so we split up the integral at <em>t</em> = √11 as

and by the fundamental theorem of calculus, since we know <em>v(t)</em> is the derivative of <em>s(t)</em>, this reduces to

Step-by-step explanation:
PEMDAS
parentheses, exponents, multiplication, division, addition, subtraction.
first multiply:
2×3=6
6+4-5
Now add
6+4=10
Now subtract
10-5=5
5 is the answer
<em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helped</u></em><em><u>!</u></em><em><u> </u></em><em><u>:</u></em><em><u>)</u></em>
the student needed to place a ten outside the radical, as a perfect square of 100 composes 200. This way, a two should be left under the radical sign. Also, this would be about 14.1 because 14^2 is 196 and 15^2 is 225. The correct answer must be less than 225, more than 196, but closer to 196. Therefore, a .1 is added to the 14