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3 years ago

What is a derivative.

1 answer:

3 0

Value from the performance of an underlying entity. This underlying entity can be an asset, index, or interest rate, and is often simply called the underlying

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5 stars and a thank you

anzhelika [568]

Answer:

Step-by-step explanation:

4 0

3 years ago

PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!

jasenka [17]

Simplified it should be 4x^10y^8

3 0

3 years ago

Write the expression in complete factored form<br><br> 4u^2(a-3)+q(a-3)

Sauron [17]

[ Answer ]

$\boxed{\bold{4au^{2} \ - \ 12u^{2} \ + \ aq \ - \ 3q}}$

[ Explanation ]

Factor: $4u^{2}$ (a - 3) + q(a - 3)

-------------------------------------

Expand $4u^2\left(a-3\right)$ : $4au^2-12u^2$

$4au^2-12u^2+q\left(a-3\right)$

Expand

$q\left(a-3\right)$ : $aq-3q$

Answer

$4au^2-12u^2+aq-3q$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

3 years ago

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

3 years ago

Find y in the line through (4,y) and (7,2) has a slope of 6

Alenkasestr [34]

Answer:

The value of y is -16.

Step-by-step explanation:

To find the missing coordinate, we can use the slope equation and plug in all known values.

m(slope) = (y2 - y1)/(x2 - x1)

6 = (y - 2)/(4 - 7)

6 = (y - 2)/-3

Now we can solve using cross multiplication.

y - 2 = -3*6

y - 2 = -18

y = -16

8 0

3 years ago