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V125BC [204]
2 years ago
9

Write an equation in standard form given: m= -3/4 and b=5.

Mathematics
1 answer:
Dmitry [639]2 years ago
5 0

Answer:

3x+4y=20

Step-by-step explanation:

The slope-intercept equation would be:

y=mx+b

y=-3/4(x)+5

But standard form is

ax+by=c

We can obtain this by moving the -3/4(x) to the left side

\frac{3x}{4} +y=5

Multiply both sides by 4 to get rid of the fraction

3x+4y=20

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There are four blue marbles, an unknown number of red (r) marbles, and six yellow marbles in a bag. Which expression represents
MAXImum [283]

Answer:

There are a total of 4 + r + 6 marbles in the bag

The probability of a blue is  \frac{4}{10+r}  

The probability of a red is  \frac{r}{10+r}  

The probability of choosing a blue, replacing it and then a red is

\frac{4}{10+r} × \frac{r}{10+r}  =  [tex]\frac{4r}{100+20r+ r^{2} /[tex]

Step-by-step explanation:

6 0
3 years ago
Use synthetic division to perform (x^4 - 3x + 5) = (x - 4).
Anastaziya [24]

Answer:

C is correct

Step-by-step explanation:

4 0
3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
Pls HELP AND EXPLAIN BRAINLIEST AND 15 POINTS
zhuklara [117]
The first one is 7.4 . 39/5=7 and 4 change so 7.4 . The second one is 1.67 . 5/3 is 1.6 repeated and rounded to the nearest houndredth is 1.67
7 0
2 years ago
An online retailer sells two packages of protein bars.
krok68 [10]
In order to find the price per bar, we divide the price by the amount of bars.  For the first one:

15.37/10 = $1.54 per bar

The second package:

15.35/12 = $1.28 per bar.

The 10-pack costs $1.54 per bar and the 12-pack costs $1.28 per bar.  The 12-pack has the better price per bar.

Now, let's look at the price per ounce.  We do this in a similar way.  We find the total amount of ounces in the package, and divide the price by the number of ounces.

In the first package, we multiply 10*2.1=21.  We have 21 ounces in the first package.  Now we divide 15.37/21.  In the first package, we have 0.73 dollars per ounce.

Now, let's look at the second package.  We start by multiplying 1.4*12=16.8.  There are 16.8 ounces in the package.  Now, we divide 15.35/16.8=0.91.  So, in the second package, we have 0.91 dollars per ounce.

The cost per ounce of the 10-pack is $0.73 and the cost per ounce of the 12-pack is $0.91.  The first package has the better price per ounce.

The better explanation is the second one, because I prefer the lower price per ounce, I think that the 1st pack is the better buy.
5 0
3 years ago
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