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2 years ago

Write an equation in standard form given: m= -3/4 and b=5.

Mathematics

1 answer:

Dmitry [639]2 years ago

5 0

Answer:

3x+4y=20

Step-by-step explanation:

The slope-intercept equation would be:

y=mx+b

y=-3/4(x)+5

But standard form is

ax+by=c

We can obtain this by moving the -3/4(x) to the left side

$\frac{3x}{4} +y=5$

Multiply both sides by 4 to get rid of the fraction

3x+4y=20

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Sin 2x=

loris [4]

Answer:

A,C

Step-by-step explanation:

sin 2x=sin (x+x)=sinx cos x+cos x sin x=2 sin x cos x

or =2 cos x sin x

[sinx cox=cos x sin x ]

6 0

3 years ago

A student from the community college is selected at random. Find the probability that the student is at last 31. Round approxima

12345 [234]

Answer:

0.077

Step-by-step explanation:

From the table :

Number of students aged 31 - 35 = 60

Number of students over 35 = 26

Total number of students = total possible outcomes = 1123

Required outcome = (students aged 31 - 35) + over 35 = 60 + 26 = 86

Probability = required outcome / Total possible outcomes

Probability (at least 31) = 86 / 1123 = 0.0765

= 0.077 (3 decimal places)

7 0

3 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

4 years ago

Helpppp pleaseeee xxxxx

ivolga24 [154]

Answer:

b=7 b=26 b=25

Step-by-step explanation:

8 0

3 years ago

Tan(x)= 3/2 <br> Find X <br> Plz help

Novosadov [1.4K]

56.30

With a calculator, press second or shift and then tan to find the degrees.

7 0

3 years ago