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2 years ago

9

I will mark brainly, help me with this question please.

1 answer:

QveST [7]2 years ago

5 0

Answer:

15 and 3

Step-by-step explanation:

<u>Create system of equations:</u>

$a=5b$

$a+b=18$

<u>Substitute:</u>

$5b+b=18$

$6b=18$

$b=3$

<u>Substitute:</u>

$a=5(3)$

$a=15$

Therefore, the two numbers are 15 and 3

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11d=81-16d how do you solve

bija089 [108]

<span>11d=81-16d
Add 16d to both sides
27d=81
Divide 27 on both sides
Final Answer: d = 3</span>

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3 years ago

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What is the formula of x<br>

tensa zangetsu [6.8K]

Isolate "x" on one side of the algebraic equation by dividing the number that appears on the same side of the equation as part of "x."

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3 years ago

Please help and show all work.

Stels [109]

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2 years ago

Find the indicated probability.

natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

<u>Recall:</u>

Binomial Distribution --> $P(k)={n\choose k}p^kq^{n-k}$
$P(k)$ denotes the probability of $k$ successes in $n$ independent trials
$p^k$ denotes the probability of success on each of $k$ trials
$q^{n-k}$ denotes the probability of failure on the remaining $n-k$ trials
${n\choose k}=\frac{n!}{(n-k)!k!}$ denotes all possible ways to choose $k$ things out of $n$ things

<u>Given:</u>

$n=10$
$k=4$
$p^k=0.53^4$
$q^{n-k}=(1-0.53)^{10-4}=0.47^6$
${n\choose k}={10\choose 4}=\frac{10!}{(10-4)!4!}=210$

<u>Calculate:</u>

$P(4)=(210)(0.53^4)(0.47^6)=0.1786117069\approx0.179$

Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

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1 year ago

How many solutions does the following equation have? <br>-2z+10+7z=16z+7

BARSIC [14]

Make all a and constant number in different side
10-7=16z-7z+2z
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z=3/11

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3 years ago

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