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shepuryov [24]
2 years ago
9

I will mark brainly, help me with this question please.​

Mathematics
1 answer:
QveST [7]2 years ago
5 0

Answer:

15 and 3

Step-by-step explanation:

<u>Create system of equations:</u>

a=5b

a+b=18

<u>Substitute:</u>

5b+b=18

6b=18

b=3

<u>Substitute:</u>

a=5(3)

a=15

Therefore, the two numbers are 15 and 3

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Solve for h: v = pi squared multiplied by h h = V multiplied by pi over r squared h = V over pi r squared h = V plus pi r square
alexandr1967 [171]

Hello from MrBillDoesMath

Answer:

See below for steps.

Discussion:

As I understand the problem statement we have a cylinder of height h and radius r. The volume of the cylinder is given by the formaul:

V = (pi * r^2) h

Divide both sides by (pi * r^2):

V\ (pi * r^2)) =     ( (pi * r^2) * h ) \ ((pi * r^2)   =>

V\ (pi * r^2)  = 1 * h = h  as  (pi * r^2)   \ (pi * r^2))

Therefore, h =  V\ (pi * r^2)



Thank you,

Mr. B


7 0
3 years ago
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Question 2 pater romuli remique erat ______. question 2 options: 1) mars 2) numitor 3) amulius 4) pastor save question 3 which i
Mamont248 [21]
<span>"Pater romuli remique erat _______" translates as "The father of Romulus and Remus is____". The answer is 1) Mars. According to myth Rhea Silvia, who is the mother of the two brothers, claimed that the father of her children was the god Mars.</span>
3 0
3 years ago
Cos(0°) = sin(0°) = tan(0°) =
MrMuchimi
Cos(0)= 1
sin(0)= 0
tan(0)= 0

P.S I don’t have the degree symbol on my phone, sorry.
4 0
3 years ago
Rolling a 6-sided die and counting the number of each outcome that occurs is a bionomial random variable. True or False? Which o
il63 [147K]

Answer:

False.

Step-by-step explanation:

This is NOT an example of a binomial random variable, because a binomial random variable can only have TWO possible outcomes: success or failure. In the case of rolling a die, there are SIX possible outcomes: 1, 2, 3, 4, 5, or 6.

So, rolling a 6-sided die and counting the number of each outcome that occurs is NOT a binomial random variable.

Hope this helps!

7 0
3 years ago
HELP A.S.A.P!!!! The data to represent average test scores for a class of 16 students includes an outlier value of 78. If the ou
kolezko [41]

When the outlier is removed The mean would increase.

<u>Step-by-step explanation:</u>

Outliers are the value that lies outside the set of data. i.e. the data doesn't fit in the group.

Removing outliers can affect mean more than median. Because outlier removal sometimes affect the median but in a small percentage or sometimes it will remain the same.

Let us prove, consider 16 values one with 78 and other 15 with values nearly 85, 84 that will give the mean value as 84.

78, 84, 82, 86, 84, 85, 83, 86, 82, 85, 84, 83, 86, 85, 86, 85.

Mean =\frac{Sum of the values}{Number of values}.

Mean =\frac{78+84+82+86+84+85+83+86+82+85+84+83+86+85+86+85}{16}.

Mean =\frac{1344}{16}.

Mean = 84.

Remove 78 from the data set then the data set is 84, 82, 86, 84, 85, 83, 86, 82, 85, 84, 83, 86, 85, 86, 85 and number of data is reduced to 15.

Mean =\frac{84+82+86+84+85+83+86+82+85+84+83+86+85+86+85}{15}.

Mean =\frac{1266}{15}.

Mean = 84.4.

The mean is increased.

8 0
3 years ago
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