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Rudik [331]
3 years ago
8

Order from least to greatest -3, 1/6, -1/6, 0.5

Mathematics
2 answers:
Rzqust [24]3 years ago
6 0
This is the answer -1/6, -3, 1/6, .5,
Debora [2.8K]3 years ago
3 0
-3, -1/6, 1/6, 0.5 is least to greatest
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In an article appearing in Today’s Health a writer states that the average number of calories in a serving of popcorn is 75. To
Ymorist [56]

Answer:

t=\frac{78-75}{\frac{7}{\sqrt{20}}}=1.917  

The degrees of freedom are given by:

df= n-1 = 20-1=19

The p value would be given by:

p_v =2*P(t_{19}>1.917)=0.0704  

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 75 and the best option would be:

a. No

Step-by-step explanation:

Information given

\bar X=78 represent the sample mean

s=7 represent the sample standard deviation

n=20 sample size  

\mu_o =75 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to check if the true mean is different from 75, the system of hypothesis would be:  

Null hypothesis:\mu =75  

Alternative hypothesis:\mu \neq 75  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing we got:

t=\frac{78-75}{\frac{7}{\sqrt{20}}}=1.917  

The degrees of freedom are given by:

df= n-1 = 20-1=19

The p value would be given by:

p_v =2*P(t_{19}>1.917)=0.0704  

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 75 and the best option would be:

a. No

8 0
3 years ago
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