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goldenfox [79]
3 years ago
8

Create and solve a story problem about the runner who is training for a race include at least one fraction in your story

Mathematics
1 answer:
vfiekz [6]3 years ago
5 0

Answer:

Runner A ran 3 miles everyday whilst his mate ran 3 1/2. How long till they both run the same distance?

Step-by-step explanation:

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What is the value of the variables?
iren [92.7K]

Answer:

x=9 and w=12

Step-by-step explanation:

To solve for w and x, create proportions between the two similar triangles.

\frac{Big Side}{Big Side} =\frac{little side}{little side}

where Big represents the bigger triangle an little represents the smaller triangle.

\frac{8}{16}=\frac{w}{12+w}

Cross multiply and solve for w.

8(12+w)=16(w)

96 + 8w = 16w

96 + 8w - 8w = 16w - 8w

96 = 8w

w=12

Repeat with a new proportion.

\frac{8}{22}=\frac{12}{24+x}

Cross multiply and solve for x.

8(24+x)=22(12)

192 + 8x = 264

8x = 72

x=9

6 0
3 years ago
Which of the following expressions is equivalent to the one shown below? (4^3)^5
Effectus [21]
Answer: 262,144
explanation: (4^3) = 64
64^5 = 262,144
6 0
3 years ago
Two jars of sweets have the same amount of sweets inside.
Serga [27]

Answer:

4 sweets are orange in jar B

Step-by-step explanation:

8 0
2 years ago
3 times the sum of a number and 4
Lyrx [107]

Answer:

3(4+x)

which can be simplified to 12+3x

4 0
3 years ago
Which of the following functions have a vertical asymptote for values of Ø such that cos Ø = 1?Select all that apply.
igomit [66]

Answer:

y=\cot \theta and y=\csc \theta

Step-by-step explanation:

Note that if \cos \theta=1, then \sin \theta=0.

Functions y=\cos \theta,\ \ y=\sin \theta do not have vertical asymptotes at all.

Vertical asymptotes have functions y=\tan \theta,\ \ y=\cot \theta,\ \ y=\sec \theta,\ \ y=\csc \theta.

Functions y=\tan \theta and y=\sec \theta have the same vertical asymptotes (when \cos \theta =0).

Functions y=\cot \theta and y=\csc \theta have the same vertical asymptotes (when \sin \theta =0). See attached diagram

3 0
3 years ago
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