Answer:
C. ∆ABD ≅ ∆CBD by the SSS Postulate
Step-by-step explanation:
We can prove that ∆ABD and ∆CBD congruent by the SSS Postulate.
The SSS postulate states that of three sides in one triangle are congruent to three corresponding sides in another, therefore, the two triangles are congruent.
From the diagram shown,
AB ≅ CB,
AD ≅ CD
BD = BD
We have three sides in ∆ABD that are congruent to three corresponding sides in ∆CBD.
Therefore, ∆ABD ≅ ∆CBD by the SSS Postulate
Would you like to solve this problem or give you the description of it
Let x represent the domain
Let y represent the range.
Assume that y =a*b⁻ˣ
Set x=0:
a*b⁰ = 32
a = 32
Set x=1:
32*b⁻¹ = 24
32 = 24b
b = 32/24
Set x=2:
d = 32*(32/24)⁻²
= 32*(24/32)²
= (32*24*24)/(32*32) = 24²/32 = 576/32
= 18
Answer: 18
For this question I would put the problem into slope-intercept form or y=mx+b. So add 3x to both sides so that the equation becomes y=3x+3 Then this equation is easier to graph. the y-intercept is 3 so there is a point at (0,3). and the slope is 3 so you would go over 1 up 3. Then connect those points and you have finished the graph. Hope this helps.
