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WITCHER [35]
2 years ago
13

Dracos invested $125,000 in 2008. Each year its value increased by 5%. Which of the

Mathematics
1 answer:
bazaltina [42]2 years ago
3 0

Answer: 1002

Step-by-step explanation: 1 is equal to two so eat subtaction and you poop adding

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The slope is -2/3. :-)
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Edward deposited $7,000 into a savings account 4 years ago. The simple interest rate is 5%. How much
Oliga [24]

answer: $1,440

explanation: here’s the equation with the values in this case

>> interest = 7,000 x 0.05 x 4

after multiplying, you get 1,440, which is the simple interest

**tip: turn the rate/percent into a decimal, then multiply

8 0
3 years ago
NO LINKS!!! Please help me with these problems​
nadezda [96]
<h3>Answers:</h3>

7) Center= (-1,2) Radius= \boldsymbol{\sqrt{8}} Equation: (x+1)^2+(y-2)^2 = 8

8) Center= (3,13) Radius= 13 Equation: (x-3)^2+(y-13)^2 = 169

=========================================================

Explanation:

Problem 7

Let's find the distance from (-1,2) to (-3,4)

(x_1,y_1) = (-1,2) \text{ and } (x_2, y_2) = (-3,4)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-(-3))^2 + (2-4)^2}\\\\d = \sqrt{(-1+3)^2 + (2-4)^2}\\\\d = \sqrt{(2)^2 + (-2)^2}\\\\d = \sqrt{4 + 4}\\\\d = \sqrt{8}\\\\

This is the radius because it stretches from the center to a point on the circle, so r = \sqrt{8}

Squaring both sides will get us r^2 = 8

One useful template for a circle is the equation (x-h)^2+(y-k)^2 = r^2\\\\

(h,k) is the center

r is the radius

Let's plug in the given center (h,k) = (-1,2) and the r^2 value we found earlier.

(x-h)^2+(y-k)^2 = r^2\\\\(x-(-1))^2+(y-2)^2 = 8\\\\(x+1)^2+(y-2)^2 = 8\\\\

You can confirm this by using a tool like Desmos. See below.

------------------------------------------------------------------------

Problem 8

The endpoints of the diameter are (-2,1) and (8,25)

The center is the midpoint of these endpoints.

The midpoint of the x coordinates is (-2+8)/2 = 3

The midpoint of the y coordinates is (1+25)/2 = 13

The center is (h,k) = (3,13)

Now find the distance from the center to one of the points on the circle, let's say to (8,25)

(x_1,y_1) = (3,13) \text{ and } (x_2, y_2) = (8,25)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-8)^2 + (13-25)^2}\\\\d = \sqrt{(-5)^2 + (-12)^2}\\\\d = \sqrt{25 + 144}\\\\d = \sqrt{169}\\\\d = 13\\\\

The radius is exactly 13 units.

So,

(x-h)^2+(y-k)^2 = r^2\\\\(x-3)^2+(y-13)^2 = 13^2\\\\(x-3)^2+(y-13)^2 = 169\\\\

is the equation of this particular circle.

Visual confirmation is shown below.

8 0
3 years ago
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Brian’s school locker has a three-digit combination lock that can be set using the numbers 5 to 9 (including 5 and 9), without r
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The possible digits are: 5, 6, 7, 8 and 9. Let's mark the case when the locker code begins with a prime number as A and the case when <span>the locker code is an odd number as B. We have 5 different digits in total, 2 of which are prime (5 and 7).

First propability:
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<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with 5, 7 or 9 (three of five digits).

Second probability:
</span>P_B=\frac{3}{5}=60\%
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Square root of 0.25 in fraction form
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