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yawa3891 [41]
3 years ago
7

A company purchases a flood insurance policy for its data center. What is its risk

Computers and Technology
1 answer:
nalin [4]3 years ago
4 0

When a company purchases a flood insurance policy for its data center, the risk management decision it took is: 4) Transference.

Risk management can be defined as a process which involves identifying, evaluating, analyzing and controlling potential risks (threats) that are present in a business, which can serve as an obstacle to its capital, revenues and profits.

Basically, risk management decision typically involves prioritizing cause of action or potential threats, so as to avoid, mitigate or transfer the risk that are likely to arise from such business decisions.

The risks or threats that are faced by a business firm can be transferred to a third-party such as an insurance agency, especially to protect its assets and resources in the event of a natural disaster such as flood, fire, earthquake, etc.

In conclusion, transference is a risk management decision that occurs when  a company purchases a flood insurance policy for its data center.

Read more on risk management here: brainly.com/question/13760012

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(4 points.) Write an algorithm (i.e., step-by-step instructions) via which someone could walk or drive from some origin to some
Elis [28]

Answer:

The algorithm is as follows :

1. Record Current Position, Final Destination

2. While Current Position is not Final Destination, repeat the following:

2.1 If destination location is up then:

  2.1.1 If an obstacle is directly above you then:

     2.1.1.1 Look for alternate position (left, right, down)

     2.1.1.2 If alternate position is found then

        2.1.1.2.1 Move there

        2.1.1.2.2 Record Current Position

     2.1.1.3 If no alternate position is found then

        2.1.1.3.1 Call for help

        2.1.1.3.2 End

  2.1.2 If no obstacle is directly above you then:

     2.1.2.1 Move up

     2.1.2.1 Record Current Position

2.2 If destination location is down then:

  2.2.1 If an obstacle is directly below you then:

     2.2.1.1 Look for alternate position (left, right, up)

     2.2.1.2 If alternate position is found then

        2.1.1.2.1 Move there

        2.2.1.2.2 Record Current Position

     2.2.1.3 If no alternate position is found then

        2.2.1.3.1 Call for help

        2.2.1.3.2 End

  2.2.2 If no obstacle is directly below you then:

     2.2.2.1 Move down

     2.1.2.1 Record Current Position

2.3 If destination location is right then:

  2.3.1 If an obstacle is directly by your right then:

     2.3.1.1 Look for alternate position (down, up, left)

     2.3.1.2 If alternate position is found then

        2.3.1.2.1 Move there

        2.3.1.2.2 Record Current Position

     2.3.1.3 If no alternate position is found then

        2.3.1.3.1 Call for help

        2.3.1.3.2 End

  2.3.2 If no obstacle is directly by your right then:

     2.3.2.1 Move right

     2.3.2.1 Record Current Position

2.4 If destination location is left then:

  2.4.1 If an obstacle is directly by your left then:

     2.4.1.1 Look for alternate position (down, up, right)

     2.4.1.2 If alternate position is found then

        2.4.1.2.1 Move there

        2.4.1.2.2 Record Current Position

     2.4.1.3 If no alternate position is found then

        2.4.1.3.1 Call for help

        2.4.1.3.2 End

  2.4.2 If no obstacle is directly by your left then:

     2.4.2.1 Move left

     2.4.2.1 Record Current Position

Explanation:

<em>The algorithm is straight forward.</em>

<em>All it does is to check for available position and move into the position if there is any available.</em>

<em>It keeps checking and moving until an obstacle prevents it from moving.</em>

5 0
3 years ago
Saujani describes that women are highly underrepresented in STEM careersShe attributes this to women needing more confidence. Wh
Sedbober [7]

Answer:

have a nice day! ❤❤

Explanation:

5 0
3 years ago
The ________ is an area where you can position fields to use for filtering the PivotTable and thereby enabling you to display a
Studentka2010 [4]

Answer: FILTERS area

Explanation: PivotTable is the kind of a tool that is used for the calculation of the data by analyzing ,summarizing ,comparing it according to the pattern and the sequence of the data.In this this tool. filter is used as the component for the filtering of the data in small/minor unit by analyzing it deeply. Different filter techniques is used in analyzing of the spreadsheet in PivotTable.

3 0
3 years ago
Convert<br> 0.625 to binary
Anastaziya [24]

\huge{ \rm{Question:}}

Convert

0.625 to binary

\huge{ \rm{Answer:}}

Translate 0.625 into a fraction. We all know that 0.5 is ½. We know that the remainder, 0.125, is ⅛. Add them together, and you get ½ + ⅛ = ⅝.

Now, in binary, the positions to the right of the point are , which is ½, ¼, and ⅛ respectively.

⅝ is 5 × ⅛. 5 in binary is 101. So, ⅝ is

= 0.101

8 0
2 years ago
Write an application that determines which, if any, of the following files are stored in the folder where you have saved the exe
Elza [17]

Answer:

Here is the JAVA application that determines which if any of the following files are stored in folder where you have saved the exercises created.

import java.nio.file.*;   // used to manipulate files and directories

import java.nio.file.attribute.*;  //used to provide access to file and file attributes

import static java.nio.file.AccessMode.*;  // provides access modes to test the accessibility of a file

import java.io.IOException;  //for exception handling

class FindSelectedFiles {

public static void main(String[] args) { //start of main function

   Path f1 = Paths.get("/root/sandbox/autoexec.bat"); //creates Path object f1 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   Path f2 = Paths.get("/root/sandbox/CompareFolders.java");  //creates Path object f2 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   Path f3 = Paths.get("/root/sandbox/FileStatistics.class");   //creates Path object f3 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   Path f4 = Paths.get("/root/sandbox/Hello.doc"); //creates Path object f4 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   int count=0; //used to count the number of files found  

try{  // used to define a code chunk to be tested for errors

 f1 = Paths.get("/root/sandbox/autoexec.bat");  // Converts a path string when joined form a path string to a Path

 System.out.println(f1);  //prints the file

     /* getFileSystem method is used to return the file system that created this Path object f1 and checkAccess Verifies access and throws exception if something is wrong

 f1.getFileSystem().provider().checkAccess(f1);  

 System.out.println(f1 +" File Exists\n");  //if file exists then displays this message

 count++;  }  //adds 1 to the count of number of files found

 catch (IOException e) {  //a code chunk to be executed if error occurs in the try part

  System.out.println("File Doesn't Exist\n"); }  //if file not found displays this message

   

try{  //works same as above try block but for 2nd folder and object f2

 f2 = Paths.get("/root/sandbox/CompareFolders.java");

 System.out.println(f2);

 f2.getFileSystem().provider().checkAccess(f2);

 System.out.println(f2 +" File Exists\n");

 count++;  }

 catch (IOException e) {

  System.out.println("File Doesn't Exist\n"); }

   

try{  //works same as above try block but for 3rd folder and object f3

 f3 = Paths.get("/root/sandbox/FileStatistics.class");

 System.out.println(f3);

 f3.getFileSystem().provider().checkAccess(f3);

 System.out.println("File Exists\n");

 count++; }

 catch (IOException e) {

  System.out.println("File Doesn't Exist\n"); }

   

try{  //works same as above try block but for 4th folder and object f4

    f4 = Paths.get("/root/sandbox/Hello.doc");

    System.out.println(f4);

 f4.getFileSystem().provider().checkAccess(f4);

 System.out.println(f4 +" File Exists\n");

 count++; }

 catch (IOException e) {

  System.out.println("File Doesn't Exist\n"); }

   

   System.out.println(count+" of the files exist");  }  } //displays the number of files found

Explanation:

If you want to directly pass the file name as argument to Paths.get() method then you can use the following code:

   Path f1 = Paths.get("autoexec.bat");

   Path f2 = Paths.get("CompareFolders.java");

   Path f3 = Paths.get("FileStatistics.class");

   Path f4 = Paths.get("Hello.doc");

The program determines if any, of the files from autoexec.bat, CompareFolders.java, FileStatistics.class, and Hello.doc. are stored in the folder. If a file is found then the program displays the message File exists and add 1 to the count variable each time a file is found. If all the files are found then the program returns the count as 4 otherwise the program display the number of files found by displaying the computed final value of count in the output. Lets say all the files are found then the output of the above program is:

autoexec.bat                                                                                                                                                   autoexec.bat File Exists  

                                                                                                                                                      CompareFolders.java                                                                                                                                            CompareFolders.java File Exists                                                      

                                                                                                                                                         FileStatistics.class                                                                                                                                           File Exists                                                                                        

                                                                                                                                                     Hello.doc                                                                                                                                                      Hello.doc File Exists  

   

4 of the files exist    

8 0
3 years ago
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