X=-b/2a is the formula for finding the axis of symmetry
So x= -30/2(5)
X=-30/10
X=-3
Because the axis of symmetry is -3, we know where to place our line, and we also know that the parabola is open downwards, which means that the vertex will be maximum. To find the vertex, plug in your values with the axis of symmetry as a midway point. Plug that in for x and so you should have the following:
F(x)
Y(f(x) and y variables are interchangeable) =5(-3)^2-30(-3)+49
Solve for y(f(x))
5(-3)^2-30(-3)+49
(-3)^2=3^2
3^2*5+30*3+49
Multiply
3^2*5+90+49
Add numbers
3^2*5+139
9*5=45
45+139=184
Y=184
So, your vertex would be
(-3,184) and it would be maximum. From there you can plug in the rest of your table of values.
Step-by-step explanation:
the explanation is above
Take key note of the dots bcz some are coloured and some aren't
p(x)= x-2
g(x)= 2x^3 + 3x^2 - 11x - 6
first we have to find the zero of the polynomial of x-2
p(x)= x-2 = 0
x=2
therefore,
p(x)= 2x^3 + 3x^2 - 11x - 6
p(2)= 2*2^3 + 3*2^2 - 11*2 - 6
= 2*8 + 3*4 - 11*2 - 6
= 16 + 12 - 22 - 6
= 28-28
= 0
Hope it helped u, ^_^.
Answer:
The Alans's average for the course is 84.5
Step-by-step explanation:
We are given
There are 4 tests, A Term paper and a Final examination.
Score = 92, 78, 82, 90.
Term paper score = 80
Final examination score = 86
Weighted mean = ∑ w.f/∑w
also the sum of all the weights is 100% = 1
weighted mean = 15%*92 + 15%*78+15%*82+15%*90+20%*80+20%*86/1
= 51.3 + 33.2
= 84.5
Therefore the Alans's average for the course is 84.5
Answer:
hope it helps ......
Step-by-step explanation:
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have a great day
