Answer:
In this set of data there is no outlier, as all numbers are relatively close.
x = number of 1-cent stamps
y = number of 8-cent stamps
z = number of 12-cent stamps
We have 31 stamps all together, so x+y+z = 31.
"I have 4 more 1-cent stamps than 8-cent stamps" means we have the equation x = y+8. Whatever y is, add 8 to it to get x. Solve for y to get y = x-8.
You also have "twice as many one cent stamps as 12 cent stamps", so x = 2z. Solving for z gets you z = 0.5x
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x+y+z = 31
x+x-8+z = 31 ... y replaced with x-8
x+x-8+0.5x = 31 ... plug in z = 0.5x
2.5x-8 = 31
2.5x = 31+8
2.5x = 39
x = 39/2.5
x = 15.6
Your teacher made a typo somewhere because we should get a positive whole number result for x (since x is a count of how many 1-cent stamps we have).
60/100 / 60 are shaded out of the hundred. Simplified would be 3/5. The decimal would be 0.6.
Answer
-23745599/2
Step-by-step explanation:
Answer:
48cm
Step-by-step explanation:
take width of rectangle to be=xcm
Length will be 3x
Area of rectangle=length × width
A=3x × x =3x²
3x²=108
x²=108/3=36
x²=36
x=√36=6cm
substitute
lenth=3x=3×6=18
width=x=6cm
perimeter=2l+2w
p=2×18 + 2×6
p=36+12=48cm
