Answer:

Step-by-step explanation:
We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).
First, recall that the equation of a circle is given by:

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.
Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

Solve for <em>r: </em>
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Simplify. Thus:

Finally, add:

We don't need to take the square root of both sides, as we will have the square it again anyways.
Therefore, our equation is:

Answer:
Multiply the 27 yd × 30 yd then after the other one do the same thing but after All divide it by 17
Answer:
Square
x = 2
y = 1
Step-by-step explanation:
- All sides of the given quadrilateral are marked with identical signs so all sides are equal.
- Also, each angle is right angle.
- So it is a square.
Measures of all ll sides of a square are equal.
Therefore,
5x - 4 = 3x
5x - 3x = 4
2x = 4
x = 4/2
x = 2
5y + 1 = 2y + 4
5y - 2y = 4 - 1
3y = 3
y = 3/3
y = 1
Answer: the answer is 1-3
Step-by-step explanation: