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Maurinko [17]
2 years ago
8

Find the Value for X,Y and z using Gauss-Jordan Inversion method 2X+3Y=4 X+2Y=2

Mathematics
2 answers:
fredd [130]2 years ago
6 0

Answer:

Step-by-step explanation:

Gala2k [10]2 years ago
5 0

Answer:

x = 2 y = 0

Step-by-step explanation:

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Identify examples and non examples of the standard form of a linear expression
Nady [450]

Answer: see attachment

<u>Step-by-step explanation:</u>

The standard form of a linear equation is: Ax + By = C

where A, B, and C are INTEGERS.

The 1st, 3rd, & 4th equations are in the form Ax + By = C

The 2nd, 5th, & 6th equations are NOT in standard form.

3 0
3 years ago
What is the distance between (−10, −2) and (−4, −2) ? −14 units −6 units 6 units 14 units
Lesechka [4]

Answer:

6 units

Step-by-step explanation:

to calculate the distance d between the points use the distance formula

d = √(x₂ - x₁ )² + (y₂ - y₁)²

with (x₁, y₁ ) = (- 10, - 2) and (x₂, y₂ ) = (- 4, - 2)

d = \sqrt{(-4+10)^2+(-2+2)^2} = \sqrt{6^2+0^2} = \sqrt{36} = 6


4 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIEST
fenix001 [56]
The answer is 10. Yw
3 0
3 years ago
Assume in a certain city that housing costs have been increasing at 5.2% per year compounded annually for the past 8 years. A ho
liraira [26]

Answer:

\$173,319.50  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=8\ years\\ A=\$260,000\\ r=5.2\%=5.2/100=0.052\\n=1  

substitute in the formula above

260,000=P(1+\frac{0.052}{1})^{1*8}  

solve for P

260,000=P(1.052)^{8}  

P=260,000/(1.052)^{8}=\$173,319.50  

4 0
3 years ago
Can someone make me a histogram for this set of data. If you do I’ll mark u as the Brainliest
sergij07 [2.7K]

Answer:On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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