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spayn [35]
3 years ago
6

Can someone make me a histogram for this set of data. If you do I’ll mark u as the Brainliest

Mathematics
2 answers:
Kruka [31]3 years ago
8 0

Answer:

Attached is a file of a sample histogram compiled by <em>Social Science Statistics</em> with the values in the question inputted.

Step-by-step explanation:

Histograms are bar graphs that represent a set of values. The vertical y-axis indicate how many values there are in a certain interval, and the horizontal x-axis indicates those intervals, usually in intervals of 10, but this depends on the range of your data.

A histogram with the following forty (40) values:

37, 22, 28, 25, 53, 29, 37, 41, 54, 29, 23, 30, 37, 41, 27, 26, 39, 24, 36, 48, 45, 31, 27, 40, 38, 41, 39, 37, 30, 44, 42, 46, 53, 43, 44, 43, 49, 51, 38, 32

sergij07 [2.7K]3 years ago
7 0

Answer:On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.

Step-by-step explanation:

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See attached image. For part b, my answer is <img src="https://tex.z-dn.net/?f=h%28t%29%3D%5Cfrac%7Bt%5E2%7D%7B100%7D-%5Cfrac%7B
ArbitrLikvidat [17]

Answer:

a) shown

b) h = [sqrt(17) - (5/2)t]²

c) t = 2sqrt(17)/5 seconds

Step-by-step explanation:

V = pi × r² × h

V = pi × 5² × h

V = 25pi × h

a) dV/dt = dV/dh × dh/dt

-5pi × sqrt(h) = 25pi × dh/dt

dh/dt = -sqrt(h)/5

b) 1/sqrt(h) .dh = -5. dt

2sqrt(h) = -5t + c

t = 0, h = 17

2sqrt(17) = 0 + c

c = 2sqrt(17)

2sqrt(h) = -5t + 2sqrt(17)

sqrt(h) = [2sqrt(17) - 5t] ÷ 2

sqrt(h) = sqrt(17) - (5/2)t

Square both sides

h = [sqrt(17) - (5/2)t]²

c) empty: h = 0

0 = [sqrt(17) - (5/2)t]²

sqrt(17) - (5/2)t = 0

(5/2)t = sqrt(17)

t = 2sqrt(17)/5

t = 1.64924225 seconds

sqrt: square root

5 0
4 years ago
Find the intervals on which​ f(x) is​ increasing, the intervals on which​ f(x) is​ decreasing, and the local extrema. f (x )equa
Kaylis [27]

Answer:

f(x) is increasing in the intervals (-∞,-4) and (9,∞)

f(x) is decreasing in the ingercal (-4,9)

The local extrema is:

local max at (-4,496)

and local min at (9,-1701)

Step-by-step explanation:

In order to solve this problem we must start by finding the derivative of the provided function, which we can find by using the power rule.

if f(x)=ax^{n} then f'(x)=anx^{n-1}

so we get:

f(x)=2x^{3}-15x^{2}-216x

f'(x)=6x^{2}-30x-216

in order to find the critical points we mus set the derivative equal to zero, since the local max an min will happen when the slope of the tangent line to the given point is zero, so we get:

6x^{2}-30x-216=0

we can solve this by factoring, so let's factor that equation:

6(x+4)(x-9)=0

we can now set each of the factors equal to zero so we get:

x+4=0 and x-9=0

when solving each for x we get that:

x=-4 and x=9

These are our critical points, now we can build the possible intervals we are going to use to determine where the function will be increasing and where it will be decreasing:

(-∞,-4), (-4,9) and (9,∞)

so now we need to test these intervals in the derivative to see if the graph will be increasing or decreasing in the given intervals. So let's pick x=-5 for the first one, x=0 for the second one and x=10 for the third one.

When evaluating them into the first derivative we get that:

f'(-5)=84, this is a positive answer so it means that the function is increasing in the interval (-∞,--4)

f'(0)=-216, this is a negative anser so it means that the function is decreasing in the interval (-4,9)

f'(10)=84, this is a positive answer so it means that the function is increasing in the interval (9,∞)

Now, for the local extrema, we can see that at x=-4, the function it's increasing on the left of this point while it's decreasing to the right, which means that there will be a local maximum at x=-4, so the local max is the point (-4,496)

We can see that at x=9, the function it's decreasing on the left of this point while it's increasing to the right, which means that there will be a local minimum at x=-9, so the local min is the point (9,-1701)

7 0
3 years ago
Write an equation for the transformation of y = x.
Ivanshal [37]

Answer:

отлично вы молодец болшая у вас всё правилно

7 0
3 years ago
Convert 12 1/2% into a decimal (It isn't 12.50)<br>Convert 12 1/2% into a fraction (It isn't 25/2)
Hoochie [10]

Answer:

0.125 and 1/8

Step-by-step explanation:

To convert a percentage to a decimal, divide by 100 to move 2 decimal places to the left.

12.50% / 100 = 0.125

To convert a percentage into a fraction, rewrite the decimal number you got and put it over 1. Multiply the numerator and denominator by 1000 to move 3 decimal places to the right and get your fraction.

\frac{0.125}{1} · \frac{1000}{1000} = 125/1000

Divide the numerator and denominator by the GCF, 125, to get your simplified fraction.

125/125 = 1

1000/125 = 8

125/1000 = 1/8

6 0
3 years ago
How do I Draw the graph of the function f(x) = 3⌊x⌋ for the domain −1 ≤ x &lt; 2
oksano4ka [1.4K]
Go to the website symbolab.com 
or Mathpap.com and that should help give you your answer
8 0
3 years ago
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