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slamgirl [31]
2 years ago
6

In a new restaurant there should be two-person tables and four-person tables. For fire safety reasons, only 56 customers are all

owed in the restaurant. There can only be 17 tables. How many two-person and how many four-person tables should be set up?
​
Mathematics
1 answer:
erica [24]2 years ago
4 0

Answer:

6 2 person

11 4 person

mark as brainliet, thank you

You might be interested in
5. Maribel makes bead necklaces. She uses a
sleet_krkn [62]

Answer:

<u>A.  52 green beads; 39 yellow beads</u>

Step-by-step explanation:

See the attachment.  If we take the ratios of 4, 2 , and 3, they add to 9.  The

Green (G), Blue (B), and Yellow (Y) will have 4/9, 2/9 and 3/9 each of the total beads, 117.

G:  52 Beads

B:  26 Beads

Y:  39  Beads

6 0
2 years ago
Please please please help me with this question, this is my third time posting it.
netineya [11]

I wanna say B cause on my calc 1/3x is less steep than g(x) but idk good luck <3

3 0
3 years ago
Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
3 years ago
suppose your grandparents started a savings acct for your on first birthday with a deposit of 100. On your second birthday they
Likurg_2 [28]
1st birthday-100
2nd birthday-200
3rd birthday- 300
4th birthday- 400
5th birthday- 500
6th birthday- 600
7th birthday- 700
8th birthday- 800
9th birthday- 900
10th birthday- 1,000
4 0
3 years ago
Choose the correct sum of the polynomials (6x3 − 8x − 5) + (3x3 + 6x + 2). 9x3 − 2x − 3 3x3 + 2x + 3 3x3 − 2x − 3 9x3 + 14x + 3
harina [27]
Add the   x^3:- 6 x3 + 3x3 = 9x3
              x's:- -8x + 6x = - 2x
               -5 + 2 = -3

the first choice is the correct one
7 0
2 years ago
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