Use the compound interest formula.
A = P*(1 +r/n)^(n*t)
where P is the principal, r is the annual rate, n is the number of compoundings per year, and t is the number of years.
For the first investment, ...
A = 208,000*(1 +.08/4)^(4*5) = 309,077.06
For the second investment, ...
A = 218,000*(1 +.07/2)^(2*4) = 287,064.37
Totaling both investments at maturity, Megan has $596,141.43.
Answer:
where is the figure?
Step-by-step explanation:
I can't see a figure
His investment will be worth $1,619.69 in 10 years.
