Answer:
Minimum unit cost = 5,858
Step-by-step explanation:
Given the function : C(x)=x^2−520x+73458
To find the minimum unit cost :
Take the derivative of C(x) with respect to x
dC/dx = 2x - 520
Set = 0
2x - 520
2x = 520
x = 260
To minimize unit cost, 260 engines must be produced
Hence, minimum unit cost will be :
C(x)=x^2−520x+73458
Put x = 260
C(260) = 260^2−520(260) + 73458
= 5,858
Answer:
You need to stop relying on this website.
Step-by-step explanation:
Anytime you find a challenging problem you will automatically go to this website thus not gaining any intelligence.
The solution of the equation x2+7x is 0, -7 using the quadratic formula.
Step-by-step explanation:
x2 + 7x = 0
-b ± √
b2 - 4(ac)/ 2a
substitution,
a = 1, b = 7, c = 0
= -7 ± √(7)2 - 4(1 x 0) / 2 x 1
= - 7
± 7 / 2
x = 0 , -7
graph c
because the graph x = -2 is a vertical line at -2 on the x axis
a = 2t+32=c
b= 2*10=20+32=52oz of coffee
I think this is right
