Y= 2 4/5 or 2.8 in decimal form
We know that Marcus spent 10 hours on his homework this week so:
10 hours = 100%
Marcus is saying that he spent 110% more time doing his homework this week, in comparison to last week.
Then to see if he is correct we have to find 110% of 10 hours.
So if: 100% of 10 hours = 10 hours
And: 10% of 10 hours (equivalent to 600 minutes) = 1 hour (or 60 minutes)
Then we add the two: 10 hours + 1 hour
And we get: 11 hours
As a result, Marcus is correct; he did spend 110% more time on his homework this week.
Hope this helps! :D
Answer with explanation:
Given:
In Δ DEF, ∠3=∠4.
To prove:→ DE=E F
Proof:
1. ∠3=∠4------[Given]
2. →∠1 and ∠ 3 are Supplementary to each other.
(a)⇒∠1 + ∠ 3=180°
→∠2 and ∠ 4 are also Supplementary to each other.
(b)⇒∠2 + ∠ 4=180°
--------------------[Exterior sides in opposite rays]
3. From 1 , a and b
⇒∠ 1 = ∠ 2-------[Two Angles Supplementary to equal Angles are equal to each other]
4. 
If two angles of a Triangle are equal , then side opposite to these angles are equal.
Answer:
10x + 9
Step-by-step explanation:
3(2x + 2) +4x + 3
=> 6x + 6 + 4x + 3
=> 10x + 9
Therefore, 10x + 9 is the solved equation.
Hoped this helped.
Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
