Question

-4/3y+-2=15what is the answer 015" id="TexFormula1" title=" \frac{ - 4}{3} y + - 2 = 15" alt=" \frac{ - 4}{3} y + - 2 = 15" align="absmiddle" class="latex-formula">

Answer 1

$-\dfrac{4}{3} y + (- 2) = 15$

Evaluate the + ( -) to give - :
$-\dfrac{4}{3} y - 2 = 15$

Add 2 on both sides:
$-\dfrac{4}{3} y= 15 + 2$

Evaluate the Right Hand Side:
$-\dfrac{4}{3} y= 17$

DIvide by -3 on both sides:
$4 y= 17 \times (-3)$

Evaluate the Right Hand Side:
$4 y= -51$

Divide by 4 on both sides:
$y = -\dfrac{51}{4}$

Simplify to mixed fraction:
$y = -12\dfrac{3}{4}$