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2 years ago

Use the area of the rectangle to find the area of the triangle.

Mathematics

2 answers:

tatyana61 [14]2 years ago

6 0

Answer:

Answer is A

Step-by-step explanation:

Area of triangle = $\frac{bxh}{2}$

= $\frac{10x5}{2}$

=25

Area of rectangle = bxh

=10x5

= 50

OLEGan [10]2 years ago

5 0

Answer:

Step-by-step explanation:

10x5=50cm^2 which is the rectangle

<h3>1 triangle is half of the rectangle so $50cm^{2}$ divided by 2= $25cm^2$ </h3>

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A photographer offers a photo shoot for a $85 flat fee. Customers may purchase prints for $5 per sheet. How many sheets can a cu

professor190 [17]

To find the answer you must first make the equation which is

(5x)+85=150

subtract 85 from 150

(5x)=65

now divide 65 by 5

resulting in the answer

X=13

To check this

(5 x 13)+85=160

(5x)+85≤150

4 0

3 years ago

Emily, Jean, and Amanda live in apartments on the 5th, 6th and 7th floors. One girl likes basketball, one likes football, and th

ss7ja [257]

Answer:

Assuming you mean baseball in stead of basketball, if must be the 5th floor.

Step-by-step explanation:

"The girl on the fifth floor thinks soccer is boring" implies that on the 5th floor lives the football or baseball fan. However, it cannot be the football fan since it is already known that she lives on 6th.

So the baseball fan, which is Jean, lives on 5th.

3 0

3 years ago

Find DY divided by DX by implicit differentiation y=sinxy

amm1812

Answer:

Step-by-step explanation:

$y = sin(xy)\\\frac{d}{dx}y=cos(xy)(\frac{d}{dx}(xy))\\ \frac{d}{dx}y = cos(xy)(y + x*\frac{d}{dx}y)\\ write \: \frac{d}{dx}y \: as\:y'\\y' = cos(xy)(y+xy')\\y' = ycos(xy) + xy'cos(xy) \\y'-xy'cos(xy) = ycos(xy)\\y'(1-xcos(xy)) = ycos(xy)\\\\y' = \frac{ycos(xy)}{1-xcos(xy)}$

6 0

3 years ago

I don’t understand please help me and give the answer

barxatty [35]

Which question do u need help with

4 0

3 years ago

For the triangle shown below, complete the following table.

dem82 [27]

Answer:

Step-by-step explanation:

In the given triangle

With reference angle A

perpendicular (P) = 3

hypotenuse (h) = 5

So sin A = p/h = 3/5

and

With reference angle C

perpendicular (p)= 4

hypotenuse (h) = 5

Sin C = p/h = 4/5

hope it helps :)

3 0

3 years ago