The answer is choice A.
We're told that the left and right walls of the cube (LMN and PQR) are parallel planes. Any line contained in one of those planes will not meet another line contained in another plane. With choice A, it's possible to have the front and back walls be non-parallel and still meet the initial conditions. If this is the case, then OS won't be paralle to NR. Similarly, LP won't be parallel to MQ.
Your answer is 25% <span> of change in the price of a radio</span>
3x+7y=-6 -7x+3y=26 -4x+4y=-32 +4x on both sides and you end up with 4y=-32+4x now divide both sides by 4 and you get y=-8+x then to incorporate that in one of the problems 3x+7(-8+x)=-6 do the distributive property with the 7 into the () and you get 3x-56+7x=-6 now add all common variables and get 10x-56=-6 now add 56 to both sides and you get 10x=50 now divide by 10 on both side and you get x=5 now for getting y to equal a number instead of an equation 3(5)+7y=-6 15+7y=-6 subtract 15 on both sides to get 7y=-21 not divide by 7 on both sides to get y=-3 your answers are y=-3 and x=5
Line segment of length k is divided into 3 equal parts.
so first segment is 0-k/3 and third segment is 2/3k-k
so mid-pt of 1st = k/6 and 3rd = 5/6k
so the distance in between = 5/6k-k/6 = 4/6k = 2/3k
