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lapo4ka [179]
3 years ago
7

If a rectangle measures 12 meters by 16 meters, what is the length, in meters, of the diagonal of the rectangle?

Mathematics
1 answer:
Serggg [28]3 years ago
5 0

Answer:

20 meters

Step-by-step explanation:

use the Pythagorean theorem:

a^2+b^2=c^2\\\\12^2 + 16^2 = c^2\\\\144 + 256 = c^2\\\\c^2 = 400\\\\c = 20

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How would you solve cos(5x)=sin(10x) ?
Tomtit [17]
We will use double angle identities:
cos (5x ) = sin (10x )   
cos (5x ) = 2 cos (5x ) sin ( 5x )
cos ( 5 x) - 2 cos ( 5 x ) sin ( 5x ) = 0
cos ( 5 x ) · [ 1 - 2 sin (5 x) ] = 0
cos ( 5 x ) = 0                    or :       1 - 2 sin (5 x) = 0
5 x = π/2 +kπ,  k∈Z                        sin (5 x) = 1/2
x1 = π/10 + kπ/5                           5 x = π/6+2kπ    , k∈ Z
                                                       5 x = 5π/6 +2kπ , k∈ Z
                                                       x 2 = π/30 +2kπ/5
                                                       x 3 = π/9  + 2kπ/5
4 0
3 years ago
LA DISTANCIA ENTRE LA TIERRA YLA LUNA ES DE 384 392 KM. LOS AUSTRONAUTAS DE LA APOLO XL SALIERON EL 16 DE JULIO DE 1969 DESDE EL
KengaRu [80]

Complete question :

la distancia entre la tierra y la luna es de 384 392 km. Los astronautas de la Apolo XL salieron el 16 de julio de 1969 desde el Centro Espacial Kennedy y al alcanzaron la orbita el 19 de julio de 1969. Suponiendo que cada dia recorrieron la misma cantidad de kilometros cuantos kilometros recorrieron por dia

Responder:

128130,66 kilometros

Explicación paso a paso:

Dado que:

Distancia entre la tierra y la luna = 384,392 km

Tiempo empleado = (19 de julio - 16 de julio) mismo año = 3 días

Velocidad = distancia / tiempo

El tiempo empleado es (3 * 24) = 72 horas

Por lo tanto,

velocidad = 384,392 / 72

= 5338,7777 kilómetros por hora

Dado que se supone que la distancia recorrida diariamente es la misma m:

El número de kilómetros recorridos por día:

5338,7777 kilómetros por hora * 24

= 128130,66 kilometros

4 0
3 years ago
Need help answering this math problem.
Fed [463]
The second bubble is the answer
4 0
3 years ago
Define z_alpha to be a z-score with an area of alpha to the right. For Example: z_0.10 means P(Z > z_0.10) = 0.10. We would a
Reptile [31]

Answer:

a) P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

And for this case the two values are :z_{crit}= \pm 1.96

b) P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

c) For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

And for this case the two values are :z_{crit}= \pm 1.96

Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

6 0
3 years ago
1. Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer t
Mazyrski [523]

Answer:

Part (A): The required inequality is T < 35 or t >40.

Part (B): The correct option is C) Only x=7.

Part (C) |x+1|+5=2 has no solution; |4x+12|=0 has one solution; |3x|=9 has two solution.

Step-by-step explanation:

Consider the provided information.

Part (A)

Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer than 40°F is an unsafe food practice.

The union is written as A∪B or “A or B”.

The intersection of two sets is written as A∩B or “A and B”

We need to determine the inequalities represent the union of these improper storage.

That means we will use A∪B or “A or B”.

The improper storage temperatures is when temperature is less than 35°F or greater than 40°F.

Hence, the required inequality is T < 35 or t >40.

Part (B) 15| x-7|+4=10|x-7|+4

Solve the inequality as shown below:

Subtract 4 from both sides.

15| x-7|+4-4=10|x-7|+4-4

Subtract 10|x-7| from both sides

15\left|x-7\right|-10\left|x-7\right|=10\left|x-7\right|-10\left|x-7\right|

5\left|x-7\right|=0\\\left|x-7\right|=0\\x=7

Hence, the correct option is C) Only x=7.

Part (C) Match the solution,

\left|x+1\right|+5=2

Subtract 2 from both sides.

\left|x+1\right|=-3

Absolute value cannot be less than 0.

Hence, |x+1|+5=2 has no solution.

|4x+12|=0

4x+12=0

x=-3

Hence, |4x+12|=0 has one solution.

|3x|=9

\mathrm{If}\:|u|\:=\:a,\:a>0\:\mathrm{then}\:u\:=\:a\:\quad \mathrm{or}\quad \:u\:=\:-a

3x=-9\quad \mathrm{or}\quad \:3x=9\\x=-3\quad \mathrm{or}\quad \:x=3

Hence, |3x|=9 has two solution.

3 0
3 years ago
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