Answer:
(x-3)^2 + (y+2)^2 = 9^2
Step-by-step explanation:
x^2 -6x+y^2+4y-68 = 0
Complete the square
x^2 -6x+y^2+4y-68+68 = 0+68
x^2 -6x+y^2+4y = 68
Find the term to add for x
-6 /2 = -3 -3^2 = 9
Find the term to add for y
4/2 =2 2^2 = 4
Add 9 and 4
x^2 -6x+9+y^2+4y+4 = 68+9+4
(x-3)^2 + (y+2)^2 = 81
(x-3)^2 + (y+2)^2 = 9^2
The standard form is
(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius
Answer:
2
Step-by-step explanation:
Ok so basically you want a number that is evenly divisible by 4. Or in other words 4 x ? = 691,61#
The easiest thing to do is start with a zero there and divide it by 4 to see what you get.
691,610 / 4 = 172,902.5
Since this is not evenly divisible by 4 let's round it up to the next whole number and multiply by 4
4 x 172,903 = 691,612
So the digit you can put on the end of the number is 2
Answer:
stuck on that too
Step-by-step explanation:
I use mathswatch aswell
X-2
Hope this helps!
Vote me brainliest!
For the division part:

But I think your question differs than this..
Am I right?
as your options do not include 1