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Anarel [89]
3 years ago
8

(-y+5×3)+(7.2y-9) How do you solve tjis

Mathematics
2 answers:
dybincka [34]3 years ago
4 0
First do the multiplication inside the parenthesis

(-y+15) + (7.2y-9)

Remove the parenthesis now

-y+15+7.2y-9

Simplify:

6.2y +6

So your final answer is \boxed{\sf{6.2y+6}}
olga nikolaevna [1]3 years ago
3 0
First remove the ( ) since there is a + sign before the ( ) the signs will not change work inside the ( ) -y+15+ 7.2y-9 6.2y+6
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Choose from the terms below to complete each sentence.
Sedbober [7]

5 : Dividend

6 : Divisor

7 : Quotient

8 : Product

<u>9 : 5550 Divided by 925 : 6</u>

<em>Hope this helps</em>

3 0
3 years ago
Number n is 25 less than 120% of itself. What is the value of n?
BARSIC [14]

Answer:

n = 125

Step-by-step explanation:

<u>Step 1:  Convert words into an expression</u>

Number n is 25 less than 120% of itself. What is the value of n?

25 less than 120% of itself can be represented as:  <u>1.2n - 25</u>

n = 1.2n - 25

<u>Step 2:  Add Subtract 1.2 from both sides</u>

n - 1.2n = 1.2n - 25 - 1.2n

-0.2n = -25

<u>Step 3:  Divide both sides by -0.2</u>

-0.2n / -0.2 = -25 / -0.2

<em>n = 125</em>

<em />

Answer: n = 125

5 0
3 years ago
Por qué la merece ser utilizada en la enseñanza de la matemática​
NemiM [27]

Answer:

por la vida el calculo del mundo en varias interfaz$#+×÷=€£_^¿)

5 0
3 years ago
Pls asap thank you guys very much
Pavel [41]

Answer:

-11

Step-by-step explanation:

B

3 0
3 years ago
Read 2 more answers
How do you solve this?
lutik1710 [3]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{8^?}{8^3}=\cfrac{1}{8^8}\implies \cfrac{8^?}{8^3}=8^{-8}\implies 8^?=8^3\cdot 8^{-8}\implies 8^?=8^{3-8}\implies 8^?=8^{-5}


\bf \begin{array}{llll} \textit{if the bases are the same, for}\\ \textit{the equation to be true, the}\\ \textit{exponents must also be the same} \end{array}~\hspace{5em}?=-5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{1}{r^3}=r^{-7}\cdot r^?\implies r^{-3}=r^{-7+?}\implies \stackrel{\textit{bases are the same, so are the exponents}}{-3=-7+?\implies 4=?}

7 0
3 years ago
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