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3 years ago

3x+2y-7x+33y^6 x=7 y=18

Mathematics

1 answer:

andrew-mc [135]3 years ago

5 0

Answer:

math is was invented just so school is torture

Step-by-step explanation:

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Can anyone help me?

vlada-n [284]

Answer:

a. 3.5 b. 2.25 c. 47.8 deg

Step-by-step explanation:

7 0

3 years ago

I need help with this problem! Must explain why.

OLEGan [10]

Answer:

95°

Step-by-step explanation:

Angle 1 and 4 are opposite angles, thus equal, so:

3x+10 = 4x-15 =>

x = 25

Angle 1 and 4 are 85°

Angle 4 and angle 6 are called allied (or co-interior) angles, which are supplementary, i.e., angle 6 = 180 - angle 4, so angle 6 = 95°.

Angle 6 and 7 are again opposite, so angle 7 is 95° as well!

7 0

2 years ago

Use the distributive property to simplify 7(2a + 5).

Vinil7 [7]

Answer:

14a+35

Step-by-step explanation:

7×2a=14a

7×5=35

=14a+25

3 0

3 years ago

Read 2 more answers

Can someone solve this with steps cause idk how to solve the radicals

IceJOKER [234]

$\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9$

to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.

8 0

3 years ago

Real estate ads suggest that 56 % of homes for sale have garages, 27 % have swimming pools, and 16 % have both features. a) W

Marizza181 [45]

Answer:

a) 0.4

b) 0.28

c) The events are not independent

d) The events are not mutually exclusive

Step-by-step explanation:

Hi!

Lets call:

Gar = {homes with garage}

Pool = {homes with pool},

A = {homes with pool and garage} = Gar ∩ Pool

The data we are given is:

P(Gar) = 0.56

P(Pool) = 0.27

P(A) = 0.16

a) B = {homes with garage but not pool}. This set B is the set Gar without set A: B = Gar / A

P(B) = P(Gar) - P(A) = 0.4

b) This is a conditional probability:

P(Pool | Gar) = P(Gar ∩ Pool) / P(Gar) = 0.16/0.56 = 0.28

c) To be independent events, it must be, by definition:

P(Gar ∩ Pool) = P(Gar) * P(Pool)

0.16 ≠ 0.56*0.27 = 0.15

Then, the events Gar and Pool are not independent

d) Gar and Pool are not mutually exclusive, because there are houses with both pool and garage. We know that because P(A) is not zero.

5 0

3 years ago