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Inessa [10]
3 years ago
14

Any number which is divisible by both 3 and 5 must…..

Mathematics
2 answers:
mariarad [96]3 years ago
8 0
The correct answer would be d
Mice21 [21]3 years ago
5 0

Answer:

D

Step-by-step explanation:

A is wrong because a factor of 15 is not divisible by both

B is wrong because 30 is even and divisible by both

C is wrong because 30 does not end with a 5

D is correct because there are no numbers other than multiples of 15 that doesn't lead to a decimal when you divide by those numbers

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Use synthetic division and the Remainder Theorem to find P(a). P(x) = 2x3 + 4x2 − 10x − 9; a = 3
guapka [62]

Answer:

b

Step-by-step explanation:

Use synthetic division and the Remainder Theorem to find P(a). P(x) = 2x3 + 4x2 − 10x − 9; a = 3

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8 0
3 years ago
A) Find all zeros of P, real and complex. (Enter your answers as a comma-separated list.
lara31 [8.8K]

Answer:

steps below

Step-by-step explanation:

x⁶ - 7x³ - 8 = (x⁶ + x³) - (8x³ + 8)

                  = x³ (x³+1)-8(x³+1)

                  = (x³ - 2³)(x³ + 1)

                  = (x-2)(x²+2x+4)(x+1)(x²-x+1)

(x-2)(x²+2x+4)(x+1)(x²-x+1) = 0

<u>x= -1 or x = 2</u>   ... roots

or    x²+2x+4=0   or    x²-x+1=0  

x²+2x+4=0

x = (-2±√4-16)/2 = <u>-1 ± √3 i</u>   ... complex roots

x²-x+1=0

x = (1±√1-4)/2 = <u>1/2 ± (√3)i / 2</u>   ... complex roots

<u />

b) P(x) = x⁶ - 7x³ - 8

           = <u>(x-2)(x²+2x+4)(x+1)(x²-x+1)</u>

           = (x+1)(x-2)(x-(-1 + √3 i))(x-(-1 - √3 i)(x-(1/2 + (√3)i / 2))(x-(1/2 - (√3)i / 2))

6 0
3 years ago
Please help 14 points
ELEN [110]

Answer:

3 over 8 (0.375)

8 0
3 years ago
Find A and B please help
TiliK225 [7]

Answer: a=124 and b=62

Step-by-step explanation:

5 0
2 years ago
What is the slope of the line that passes through the points (-8,-3)and(-12,-3) write your answer in the simplest form
Andrej [43]

Answer:

m=0

Step-by-step explanation:

Given the points

(-8,-3)and(-12,-3)

The slope between the points  (-8,-3) and (-12,-3) can be determined

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-8,\:-3\right),\:\left(x_2,\:y_2\right)=\left(-12,\:-3\right)

m=\frac{-3-\left(-3\right)}{-12-\left(-8\right)}

m=0

4 0
3 years ago
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