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2 years ago

Which of the following factors is a factor of the expression x^2+5x-6

Mathematics

1 answer:

sergeinik [125]2 years ago

5 0

Answer:

HOLA MATE HERE IS YOUR ANSWER....

{x}^{2} - 5x - 6x

−5x−6

WE WILL SOLVE IT BY MIDDLE TERM SPLITTING

product = {6x}^{2}product=6x

Sum = 5x

{6x}^{2} \times {1x}^{2} = {6x}^{2}6x

×1x

=6x

-6x + 1x = 5x

ANSWER :

{x}^{2} - 6x + 1x - 6x

−6x+1x−6

NOW WE CAN FURTHER CONTINUE IT BY TAKING COMMON

SO,

x(x - 6) + 1 (x - 6)

Answer :

(X+1)(X-6)

PLEASE MARK AS BRAINLIEST

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Kobotan [32]

12.568% is the correct answer

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3 years ago

Read 2 more answers

Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3

maria [59]

Answer:

$a_1=4\\\\a_2=0\\\\a_3=3$

Explanation:

The equation is:

$a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}$

and

$a_4=-7, a_5=-36, a_6=-85$

1. Subsittute n = 6 into the equation:

$a_6=3a_{5}-5a_{4}-4a_{3}$

Now subsititute the known values:

$-85=3(-36)-5(-7)-4a_{3}$

You can solve for $a_3$

$-85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3$

2. Substitute n = 5 into the equation:

$a_5=3a_{4}-5a_{3}-4a_{2}$

Substitute the known values and solve for $a_2$

$-36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0$

3. Substitute n = 4 into the equation, subsitute the known values and solve for $a_1$

$a_4=3a_{3}-5a_{2}-4a_{1}$

$-7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4$

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3 years ago

I need to find a number that the "n" represents. The problem is 9/12=n/32

likoan [24]

The given equation is

$\frac{9}{12} = \frac{n}{32}$

Here we have to solve for n. First we need to get rid of the denominators and for that we do cross multiplication .

$9*32 = 12n$

Now we need to isolate n. And for that we need to get rid of 12, by dividing both sides by 12

$\frac{9*32}{12}=n$

$\frac{288}{12} =n$

$n=24$

And that's the required value of n .

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3 years ago

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ruslelena [56]

Answer:

Step-by-step explanation:

Let the original number = x

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago