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myrzilka [38]
3 years ago
9

Derek put 96 plastic cups in the first stack, 88

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
8 0

Answer:

72

Step-by-step explanation:

There's a constant trend of x-8. so subtract 8 from 80 and you get 72.

luda_lava [24]3 years ago
5 0

Answer:

<h2>72</h2>

Step-by-step explanation:

we can see that 8 is being - every time

all we do is 80-8

=72

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Need help please :) I’m not sure how to solve this one either
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The answer is

580|21

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A system of equations with a linear and quadratic equation must have one solution.
Ierofanga [76]
That is false because, this type of system can have one solution, two solutions, or no solutions. Graph both equations on the same coordinate plane. Identify the point of intersection, if any. 
Hope I Helped : )

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4 years ago
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translate into an algebraic expression: 120 is decreased by d% and increased by 25%. what is the result
s2008m [1.1K]

Answer:

150(1-x)

Step-by-step explanation:

120 is decreased by d%

Let x = d%

120 - 120*x

120(1-x)

Then it is increased by 25%

(120 (1-x)) +(120 (1-x))*.25

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3 years ago
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How to solve 5-2x=-4x-7
stepan [7]

Answer:

x=-6

Step-by-step explanation:

Use Substitution

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5+2x=-7

than I'ma move that 5 to the other side by making it a negative

2x=-12

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4 years ago
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When two six-sided dice are rolled, there are 36 possible outcomes. Find the probability that the sum is not 5.
zaharov [31]

Answer:

p(Not\ 5) = \frac{8}{9}

Step-by-step explanation:

Given:

Txo six-sided dice are rolled.

Total number of outcomes n(S) = 36

We need to find the probability that the sum is not equal to 5 p(Not 5).

Solution:

Using probability formula.

P(E)=\frac{n(E)}{n(S)}  ----------------(1)

Where:

n(E) is the number of outcomes favourable to E.

n(S) is the total number of equally likely outcomes.

The sum of two six-sided dice roll outcome is equal to 5 as.

Outcome as 5: {(1,4), (2,3), (3,2), (4,1)}

So, the total favourable events n(E) = 4

Now, we substitute n(E) and n(s) in equation 1.

P(5)=\frac{4}{36}

p(5) = \frac{1}{9}

Using formula.

p(Not\ E) + p(E) = 1

p(Not\ 5) + p(5) = 1

Now we substitute p(5) in above equation.

p(Not\ 5) + \frac{1}{9} = 1

p(Not\ 5) = 1-\frac{1}{9}

p(Not\ 5) = \frac{9-1}{9}

p(Not\ 5) = \frac{8}{9}

Therefore, the sum of two six-sided dice roll outcome is not equal to 5.

p(Not\ 5) = \frac{8}{9}

6 0
3 years ago
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