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slava [35]
3 years ago
9

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Mathematics
1 answer:
ollegr [7]3 years ago
8 0
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You might be interested in
Apples at the farmers’ market cost $2.50 for 5 apples or $0.70 for 1 apple.
Lynna [10]
2.50$ is the better deal. If you times 0.70$ to 5 it is 3.5$ which is more expensive
8 0
3 years ago
Read 2 more answers
A scale on a bike path shows that 3 inches represents 5 miles. How many inches on the map are equal to 30 miles
PtichkaEL [24]

Answer:

18 inches.

Step-by-step explanation:

If the ratio for inches to miles is

\frac{3}{5},

then you multiply the top and bottom by 6 to get to 30. This gets the numerator to 18 inches.

8 0
3 years ago
What is the radius of 20?<br><br> (20 is the diameter)
Goshia [24]
Well if d= 20
d=2r

so 20 = 2r

r=10

is that what you wanted, or does this have to do with a circle 

4 0
3 years ago
Read 2 more answers
suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model. A samp
Tema [17]

Answer:

3.33% per hour

Step-by-step explanation:

Use the A=Pe^rt equation. A is the end amount, so it's 1892. P is the original amount, 1700. E is a constant, around 2.72. R is the growth constant. T is the time that passed, 3 hours. You can substitute the givens into the equation and get 1892=1700e^(3r). Divide by 1700 to isolate the e. This leaves you with 1892/1700=e^(3r). Do the natural log of each side cancel the e and bring the exponent down. This leaves you with ln(1892/1700)=3r. Divide by 3 to isolate r. ln(1892/1700) is .1. .1/3 is .03333. Multiply by 100 to get a percent. 3.33 percent is your final answer.

8 0
3 years ago
Please please help me
Alex73 [517]

Answer:

x = 5.5

Step-by-step explanation:

Given 2 secants intersecting the circle from a point outside the circle then

The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is

x(x + 14) = 6(6 + 12)

x² + 14x = 6 × 18 = 108 ( subtract 108 from both sides )

x² + 14x - 108 = 0 ← in standard form

with a = 1, b = 14 and c = - 108

Using the quadratic formula to solve for x

x = ( - b ± \sqrt{b^2-4ac} ) / 2a

  = ( - 14 ± \sqrt{14^2-(4(1)(-108)} ) / 2

  = ( - 14 ± \sqrt{196+432} ) / 2

  = ( - 14 ± \sqrt{628} ) / 2

  x = \frac{-14-\sqrt{628} }{2} or x = \frac{-14+\sqrt{628} }{2}

  x = - 19.5 or x = 5.5 ( to 1 dec. place )

However x > 0 ⇒ x = 5.5

6 0
3 years ago
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