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Ipatiy [6.2K]
3 years ago
12

Sketch the following to help answer the question. Kite WXYZ has a short diagonal of XZ and a long diagonal of WY. The diagonals

intersect at point V. The length of XZ = 8cm, the length of segment WV is 6√3, and the ∠XYV = 30°. Find the exact area of kite WXYZ.

Mathematics
2 answers:
djyliett [7]3 years ago
7 0

The answer is: 40 sqr3

I know that this is correct is OW :) Ya'll have a nice day! Good luck!

HACTEHA [7]3 years ago
5 0

Answer: 69.281cm2

Step-by-step explanation: first we sketch the kite, which I have done is the picture attached

To find the area, we divide the kite into two triangles, cutting the kite at the line XZ

So we have two triangles, XWZ and XYZ

We know that finding the area of a triangle is half of it's base multiplied by the height

A = 1/2bh

For triangle XWZ we have a base of 8cm and a height of 6root3cm

Finding the area

1/2 x 8 x 6root3 = 41.569cm2

For triangle XYZ we have the base, but we don't have the height

So to get the height we use tan rule

We states that tan of an acute angle in a right angle triangle equals to the value of the length opposite the angle divided by the value of the length adjacent to it, popular known as "TOA"

Since XY and XZ are the same lengths (properties of a kite)

We can tell that XV is half of XZ

So XV = 8/2 = 4cm

We label the height we are looking for as x

So therefore

Tan30 = 4/x

xtan30 = 4

x = 4/tan30 = 6.928

So therefore

Area of triangle XYZ

1/2 x 8 x 6.928 = 27.712cm2

Adding the two Areas together = 41.569+27.712 = 69.28cm2

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Part F
mihalych1998 [28]

Answer:

The geometric mean of the measures of the line segments AD and DC is  60/13

Step-by-step explanation:

Geometric mean: BD² = AD×DC

BD = √(AD×DC)

hypotenuse/leg = leg/part

ΔADB: AC/12 = 12/AD

AC×AD = 12×12 = 144

AD = 144/AC

ΔBDC: AC/5 = 5/DC

AC×DC = 5×5 = 25

DC = 25/AC

BD = √[(144/AC)(25/AC)]

BD = (12×5)/AC

BD= 60/AC

Apply Pythagoras theorem in ΔABC

AC² = 12² + 5²

AC² = 144+ 25 = 169

AC = √169 = 13

BD = 60/13

The geometric mean of the measures of the line segments AD and DC is BD = 60/13

6 0
3 years ago
What are the answers to ther two questions??
Vlad1618 [11]
the answer is the third option, starting with degree 11.
6 0
3 years ago
Read 2 more answers
Find the slope-intercept form of the equation of the line passing through the points.
LekaFEV [45]
Plog in to y=ax+b and u will find a b
5 0
3 years ago
A ________ function specifies the relationship between the demand for a product LaTeX: x and the price of the product LaTeX: p.
Archy [21]

Answer:

Price demand function

Step-by-step explanation:

The price demand function is the function in which there is a relationship between the demand and the price of the product

The Price demand function is

= Price \times demand

= p \times x

hence, the price demand function represents that there is a relationship that lies between the demand and the price

3 0
2 years ago
Line A: y=-1/2x+3
sashaice [31]
A) For the equation y=- \frac{1}{2}x+3, the slope is - \frac{1}{2}.
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. This means that if m=- \frac{1}{2}, the slope is  - \frac{1}{2}.

B) Since this equation is in the same form, you just find what m is equal to.
Since m=2, that's the slope.

For the solution, set y=- \frac{1}{2}x+3 equal to y=2x-4, so it would be put together like this:
y=[tex]- \frac{1}{2}x+3=2x-4\\ -\frac{1}{2}=2x-7\\ 1\frac{1}{2}x=-7\\ x=-4.66667
So your answer is -4.667.
8 0
3 years ago
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