Simplify, u=Write your answer using whole numbers and variables:<br> 2p/4p

What is the probability that the system does not have a type 2defect?b.What is the probability that the system has both type 1 a

Lana71 [14]

Answer:

a. 0.93 b. 0.06 c. 0.05

Step-by-step explanation:

Probability is commonly known as the chance of success of a particular event. The probability of failure of the event can also be estimated.

(a) Probability of not having type 2 defect is: $P(A_{2}^{'})$ $= 1 - P(A_{2})$ = 1 - 0.07 = 0.93

(b) Probability of having type 1 and 2 defects is: $P(A_{1} n A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1}U A_{2}) = 0.12 + 0.07 - 0.13 = 0.06$

(c) probability pf having both type 1 and type 2 defects but not type 3 defect is:

$P(A_{1} + A_{2} + A^{'} _{3}) = P(A_{1} n A_{2}) - P(A_{1} n A_{2} n A_{3}) = 0.06 - 0.01 = 0.05$

3 0

3 years ago

An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are $E(1)= ^9C_2$ places in which the other 2 red balls can be placed.

A red ball drawn third, there are $E(3)= ^7C_2$ places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are $E(5)= ^5C_2$ places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are $E(7)= ^3C_2$ places in which the other 2 red balls can be placed.

The total number of total event is $S= ^{10}C_3$

The probability that A selects the first red ball is

$P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}$

$P(A \text{wins})=\frac{36+21+10+3}{120}$

$P(A \text{wins})=\frac{70}{120}$

$P(A \text{wins})=0.5833$

6 0

3 years ago

The scale for a map is 20 miles = 1/2 inch. The distance between two towns on the map is 3 3/4 inches. What is the actual distan

zubka84 [21]

Answer:

150 miles

Step-by-step explanation:

If 1/2 of an inch is 20 miles, we can assume that 1/4 of an inch is 10 miles, since half of 1/2 is 1/4 and 1/2 of 20 is 10.

Equipped with this information, we can divide 3 by 1/2 or multiply 3 by the reciprical, 2/1 to get how much we should multiply 20 by.

3*2=6

20*6=120

Then we can multiply 10 by 3 and add that on our answer, since there are still 3/4s left and 1/4=10 miles.

10*3=30

120+30=150

The actual distance is 150 miles.

Hope this helps!

4 0

3 years ago

Find the values of x and y.

Harrizon [31]

4x+5x = 90
9x = 90
x = 10

10y + 10 + 5x = 180
10y + 10 +5(10) = 180
10y + 60 = 180
10y = 120
y = 12

answer
<span>d) x = 10, y = 12</span>

5 0

3 years ago

Read 2 more answers

The formula for finding the perimeter of a rectangle is P = 2L + 2W. If a rectangle has a perimeter of 68 inches and the length

Artemon [7]

Answer:

Width = 10 inches

Step-by-step explanation:

Given the perimeter of a rectangle of 68 inches, and a length that is 14 inches longer than its width.

We can establish the following values to help us solve for the width of a rectangle:

Perimeter (P) = 68 inches

Length (L) = 14 + W inches

Width (W) = unknown

<h3 /><h3><u>Solve for the Width (W)</u></h3>

P = 2(L + W) ⇒ This is the same as P = 2L + 2W, except that 2 is factored out from the right-hand side.

Divide both sides by 2:

$\displaystyle\mathsf{\frac{P}{2}\:=\:\frac{2(L\:+\:W)}{2}}$

$\displaystyle\mathsf{\frac{P}{2}\:=L\:+\:W}$

Substitute the value of the Perimeter and the length (L) into the formula:

$\displaystyle\mathsf{\frac{68}{2}\:=14\:+W\:+\:W}$

Combine like terms on the right-hand side, and simplify the left-hand side of the equation:

$\displaystyle\mathsf{34\:=14\:+2W}$

Subtract 14 from both sides:

34 - 14 = 14 - 14 + 2W

20 = 2W

Divide both sides by 2 to solve for the width (W):

$\displaystyle\mathsf{\frac{20}{2}\:=\:\frac{2W}{2}}$

W = 10 inches

Therefore, the width of the rectangle is 10 inches.

<h3 /><h3><u>Double-check:</u></h3>

Verify whether the derived value for the width is correct:

P = 2L + 2W

68 = 2(14 + 10) + 2(10)

68 = 2(34) + 20

68 = 48 + 20

68 = 68 (True statement).

Thus, the length of the rectangle is 34 inches, and the width is 10 inches.

4 0

2 years ago

Simplify, u=Write your answer using whole numbers and variables: 2p/4p