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vampirchik [111]
3 years ago
13

What is the slope of the line that passes through the points (-10,0) and (-13,3)?

Mathematics
2 answers:
Pie3 years ago
5 0

Answer:

Step-by-step explanation:

(-10,0) and (-13,3)

Slope m = (y2 - y1)/(x2 - x1)

y2 = 3, y1 = 0, x2 = -13, x1 = -10

: m = (3 - 0)/(-13 + 10)

m = 3/-3

m = -1

Slope m = -1

photoshop1234 [79]3 years ago
4 0

Answer:

3/-3 basically -1

Step-by-step explanation:

do the y2-y1 / x2-1 formula and put the coordinates in and that is:

3-0 / -13- -10

or

3/-3

or -1

BTW: if the numerator and denominator are both negative,

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Show all work to identify the asymptotes and state the end behavior of the function f(x)=5x/x-25
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Using the asymptote concept, it is found that:

  • The vertical asymptote is of x = 25.
  • The horizontal asymptote is of y = 5.
  • Considering the horizontal asymptote, it is found that the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

f(x) = \frac{5x}{x - 25}

Considering the denominator, the vertical asymptote is:

x - 25 = 0 -> x = 25.

The horizontal asymptote is found as follows:

y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = \lim_{x \rightarrow \infty} 5 = 5

Hence the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

More can be learned about asymptotes and end behavior at brainly.com/question/28037814

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