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DiKsa [7]
2 years ago
9

ARAT TIETE (Simplify): V125 - V45+ V5​

Mathematics
1 answer:
Nataly [62]2 years ago
6 0

Answer:

3\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{125}

= \sqrt{25(5)}

= \sqrt{25} × \sqrt{5} = 5\sqrt{5}

\sqrt{45}

= \sqrt{9(5)}

= \sqrt{9} × \sqrt{5} = 3\sqrt{5}

Then

\sqrt{125} - \sqrt{45} + \sqrt{5}

= 5\sqrt{5} - 3\sqrt{5} + \sqrt{5} ← collect like terms

= 3\sqrt{5}

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Answer:

Statement A is correct about Sam's box and whisker plot.

Step-by-step explanation:

We have been given a box plot and we are asked to find out true statement according to the box plot.

Since we know data represented by box plot is divided in four equal parts.

Upon looking at our box plot we can see that our data is symmetric. It's median is 15, which means half the math assignments have less than 15 problems and half of the math assignments have more than 15 problems.

Interquartile range represents 50% values of data and it is the difference between upper quartile and lower quartile. IQR is not affected by outliers.

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Upon substituting given values from box plot we get,

IQR=19-11=8

From IQR we can conclude that half of the assignments contained 15 problems or fewer.Therefore, option A is the correct choice.


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