Help please immediately

A line segment has (x1, y1) as one endpoint and (xm, ym) as its midpoint. Find the other endpoint (x2, y2) of the line segment i

Tasya [4]

Answer:

(3,7) for the first line, and (12,0) for the second one.

Step-by-step explanation:

Hi Isabella,

1) The Midpoint of a line, when it comes to Analytical Geometry, is calculated as Mean of two points it follows:

$x_{m}=\frac{x_{1} +x_{2} } {2}, y_{m} =\frac{y_{1}+ y_{2} }{2}$

2) Each segment has two endpoints, and their midpoints, namely:

a) (1,-9) and its midpoint (2,-1)

b) (-2,18) and its midpoint (5,9)

3) Calculating. You need to be careful to not sum the wrong coordinates.

So be attentive!

The first line a

$2=\frac{1+x_{2} }{2}\\ 4=1+x_{2}\\ 4-1=-1+1+x_{2} \\ x_{2}=3\\-1=\frac{y_{2}-9}{2}\\-2=y_{2}-9\\+2-2=y_{2}-9+2\\ y_{2}=-7$

So (3,7) is the other endpoint whose segment starts at (1,-9)

The second line b endpoint at (-2,18) and its midpoint (5,9)

$5=\frac{-2+x_{2} }{2} \\ 10=-2+x_{2} \\ +2+10=+2-2+x_{2}\\ x_{2}=12 \\ \\ 9=\frac{18+y_{2} }{2} \\ 18=18+y_{2} \\ -18+18=-18+18+y_{2}\\ y_{2} =0$

So (12,0) it is the other endpoint.

Take a look at the graph below:

8 0

3 years ago

A tortoise makes a journey in two parts; it can either walk at 4cm/s or crawl at 3cm/s. If the tottoise walks the first part and

Ugo [173]

Answer:

120

240

Step-by-step explanation:

We call the length of first part x

Length of second part = y

In the first scenario, it took the tortoise 110 sec to walk the first part and crawl the second.

So,

We have this equation,

x/4 + y/3 = 110

We take the LCM

(3x + 4y)/12 = 110

When we cross multiply

3x + 4y = 110x12

3x + 4y = 1320 ----- equation 1

For scenario 2

x/3 + y/4 = 100

When we take the LCM

(4x + 3y)/12 = 100

We cross multiply

4x + 3y = 100x12

4x + 3y = 1200 ------ equation 2

We now have two equations and we will solve for x and y using simultaneous linear equation.

3x + 4y = 1320 ----- 1

4x + 3y = 1200 ----- 2

We subtract equation 2 from 1 to get

- x + y = 120

We make y subject

y = x + 120 ----- 3

We put the value of y in equation 3 into equation 1

3x + 4(x + 120) = 1320

3x + 4x + 480 = 1320

7x + 480 = 1320

7x = 1320-480

7x = 840

We divide through by 7

x = 840/7

x = 120

We put value of x in equation 3

y = x + 120

y = 120 + 120

y = 240

120 and 240 are the lengths of the 2 parts of the journey.

Thanks

5 0

3 years ago

Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin

ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let $\mu$ = mean duration of 15-sided union rugby games after the meeting.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

= -3

The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0

3 years ago

According to the scale on a road map, 3 cm represents 45 kilometers. if two cities measure 10 cm apart on the map, how many kilo

denpristay [2]

150 Km.

Good luck! :)

4 0

3 years ago

Help please and thank you

sergiy2304 [10]

8 is 91 because 13•7 is 91 inside is needed 91 tiles

3 0

3 years ago

Read 2 more answers