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BlackZzzverrR [31]

2 years ago

13

Toyota marketed its RAV4 hybrid model to a distinct segment of consumers as an adventurous, sporty hybrid that stands out as bei

ng uniquely different from other hybrid models. This is an example of

1 answer:

pychu [463]2 years ago

3 0

Answer:

the marketing mix variable—place

Explanation: this easy bc u just see what the variablie to the mix is times that

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You are the manager of a pizzeria that produces at a marginal cost of $6 per pizza. The pizzeria is a local monopoly near campus

Sergeeva-Olga [200]

Answer:

since the price elasticity of demand for students is -4, the the price charged to them should be:

price = [-4 / (-4 + 1)] x $6 = (-4 / -3) x $6 = $8

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price = [-2 / (-2 + 1)] x $6 = (-2 / -1) x $6 = $12

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3 years ago

Dma corporation has bonds on the market with 16.5 years to maturity, a ytm of 7.7 percent, and a current price of $1,065. the bo

bonufazy [111]

With face value equal to $ 1000, present value equal to $ 1,065, we get nper = 16.5 * 2 = 33. Rate(ytm) is equal to 7.7%/2 = 3.85%.PMT (coupon payment) = $ 42.01.Coupon rate = (42.01 / 1000) = 4.20%.Therefore, the annual coupon rate is equal to 4.2 * 2 which equates to 8.40%

7 0

3 years ago

Jeffrey is going to sell sporting apparel, which he has already purchased from manufacturers, and has signed a deal agreeing to

photoshop1234 [79]

Answer: Place.

Explanation:

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3 0

3 years ago

Read 2 more answers

Part-time workers likely result in A. inaccurately high estimates of the labor force. B. inaccurately low estimates of the labor

avanturin [10]

Answer:

Correct answer:

A. inaccurately high estimates of the labor force.

Explanation:

Part-time work is the type of work where an individual has a flexible work plan is a given company unlike the traditional full-time work. Doing such work create the impression that, there is high labour force among the various industries and sectors.<em> For example, someone might be working in two different firms under part-time basis same day which create an impression of two different individuals.</em>

5 0

3 years ago

The Beef-up ranch feeds cattle for midwestern farmers and delivers them to processing plants in Topeka,Kansas and Tulsa, Oklahom

AfilCa [17]

Answer:

a. Min Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 128 .......(1)

3x₁ + x₂ + 3x₃ ≤ 160 ........(2)

x₁ + 0x₂ + 2x₃ ≤ 32 .........(3)

6x₁ + 8x₂ + 4x₃ ≤ 256 .........(4)

3x₁ + 2x₂ + 4x₃ ≥ 64 ..........(5)

3x₁ + x₂ + 3x₃ ≥ 80 ..........(6)

x₁ + 0x₂ + 2x₃ ≥ 16 ...........(7)

6x₁ + 8x₂ + 4x₃ ≥ 128 ............(8)

x₁ ≤ 15 ...........(9)

x₂≤ 15 ...........(10)

x₃ ≤ 15 ...........(11)

x₁ , x₂, x₃ ≥ 0

b. x₁ = 15 , x₂ = 9.5 , x₃ = 8.5

c. The optimal solution is Z = 79.25

Explanation:

Given - The table is as follows :

Nutrient Feed 1 Feed 2 Feed 3
A 3 2 4
B 3 1 3
C 1 0 2
D 6 8 4

The minimum requirement per cow each month is 4 pounds of nutrient A, 5 pounds of nutrient B, 1 pound of nutrient C, and 8 pounds of nutrient D. However, cows should not be fed more than twice the minimum requirement for any nutrient each month. Additionally, the ranch can only obtain 1,500 pounds of each type of feed each month. Because there are usually 100 cows at the beef-up ranch at any given time, this means that no more than 15 pounds of each type of feed can be used per cow each month.

To find - a. Formulate a linear programming problem to determine how

much of each type of feed a cow should be fed each month.

b. Create a spreadsheet model for this problem, and solve it using

Solver.

c. What is the optimal solution?

Proof -

a.

Let feed 1 per cow per month = x₁

feed 2 per cow per month = x₂

feed 3 per cow per month = x₃

Now,

As given, The cost per pound of feeds 1,2, and 3 are $2.00, $2.50, and $3.00, respectively.

So, we have to minimize the cost , Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 4(32)

3x₁ + x₂ + 3x₃ ≤ 5(32)

x₁ + 0x₂ + 2x₃ ≤ 1(32)

6x₁ + 8x₂ + 4x₃ ≤ 8(32)

∴ we get

Min Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 128 .......(1)

3x₁ + x₂ + 3x₃ ≤ 160 ........(2)

x₁ + 0x₂ + 2x₃ ≤ 32 .........(3)

6x₁ + 8x₂ + 4x₃ ≤ 256 .........(4)

Now, as given

However, cows should not be fed more than twice the minimum requirement for any nutrient each month.

∴ we have

3x₁ + 2x₂ + 4x₃ ≥ $\frac{128}{2}$

3x₁ + x₂ + 3x₃ ≥ $\frac{160}{2}$

x₁ + 0x₂ + 2x₃ ≥ $\frac{32}{2}$

6x₁ + 8x₂ + 4x₃ ≥ $\frac{256}{2}$

and also

No more than 15 pounds of each type of feed can be used per cow each month.

⇒x₁ , x₂, x₃ ≤ 15

So,

The LPP model becomes

Min Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 128 .......(1)

3x₁ + x₂ + 3x₃ ≤ 160 ........(2)

x₁ + 0x₂ + 2x₃ ≤ 32 .........(3)

6x₁ + 8x₂ + 4x₃ ≤ 256 .........(4)

3x₁ + 2x₂ + 4x₃ ≥ 64 ..........(5)

3x₁ + x₂ + 3x₃ ≥ 80 ..........(6)

x₁ + 0x₂ + 2x₃ ≥ 16 ...........(7)

6x₁ + 8x₂ + 4x₃ ≥ 128 ............(8)

x₁ ≤ 15 ...........(9)

x₂≤ 15 ...........(10)

x₃ ≤ 15 ...........(11)

x₁ , x₂, x₃ ≥ 0

b.)

We use simplex method calculator to solve this LPP Problem

we get

x₁ = 15 , x₂ = 9.5 , x₃ = 8.5

c.)

The optimal solution is Z = 79.25

4 0

2 years ago