assuming the rest of your math is correct, the cone would have an area of roughly 212 sq in and the bowl roughly 157 sq inches. Therefore the one with less area is cheaper to make
Idk how to do this I forgot
Answer:
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Step-by-step explanation:
in the question the scale factor is 4 so that means it is a dilation (getting larger) because the scale factor is >1
You have to find the LCD or least common denominator.
In this case the LCD would be (x-6)(x+5).
Problem: x/ x-6 - 1/x+5
Step 1: multiply x-6 to the numerator and denominator of 1/x+5
1(x-6)/ (x+5)(x-6)
Step 2: multiply x+5 to the numerator and denominator of x/x-6
x(x+5)/ (x+5)(x-6)
After all that, this is how the problem should look now
x(x+5)/ (x-6)(x+5) - 1(x-6)/ (x-6)(x+5)
If you simplify this you get
x²+5x-x+6/ (x-6)(x+5)
If you subtract both 5x-x (like terms) you get
x²+4x+6/ (x-6)(x+5)
which is the answer
2x + 4 = 3(x - 2) + 1
2x + 4 = 3x - 6 + 1
2x + 4 = 3x - 5
2x - 3x = -5 - 4
-x = -9
x = 9
one solution
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4(x + 3) = 3x + 17
4x + 12 = 3x + 17
4x - 3x = 17 - 12
x = 5
one solution
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3x + 4 + 2x = 5(x - 2) + 7
5x + 4 = 5x - 10 + 7
5x + 4 = 5x - 3
5x - 5x = -3 - 4
0 = -7
no solutions
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2(1 + 5x) = 5(2x - 1)
2 + 10x = 10x - 5
10x - 10x = -5 - 2
0 = -7
no solution
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-18 + 15x = 3(4x - 6) + 3x
-18 + 15x = 12x - 18 + 3x
-18 + 15x = 15x - 18
15x - 15x = -18 + 18
0 = 0
infinite solutions
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-10 + 5x = 5(x - 3) + 5
-10 + 5x = 5x - 15 + 5
-10 + 5x = 5x - 10
5x - 5x = -10 + 10
0 = 0
infinite solutions
===============
if the variables cancel out leaving u with an untrue statement, like 0 = 4 or 2 = 6, then u will have no solutions
if the variables cancel out leaving u with a true statement, like 2 = 2 or 4 = 4, then u will have infinite solutions
if u end up with a variable equaling a number, then u have 1 solution
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3x + 4 = 2x + 2
3x - 2x = 2 - 4
x = -2
one solution
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3(x + 2) + 1 = 3x + 7
3x + 6 + 1 = 3x + 7
3x + 7 = 3x + 7
3x - 3x = 7 - 7
0 = 0
infinite solutions
============
2x + 3 = 2x + 4 + 1
2x + 3 = 2x + 5
2x - 2x = 5 - 3
0 = 2
no solutions
