This equation is separable, as

Integrate both sides; on the left, expand the fraction as

Then


Since
, we get

so that the particular solution is

Answer:
Given :
The length of a rectangle is 4 cm more than its width
The area of the rectangle is 96 cm²
To Find :
Width of the rectangle.
Solution :
Let the length of the rectangle be x cm.
Let the breadth of the rectangle be y cm.
Case 1:
➣
➣ _____(1)
Case 2 :
We have the formula for area of the rectangle as follows :
Where,
l = length → x cm
b = breadth → y cm.
➣
➣
Substitute, x = 96/y in equation 1,
➣
➣
➣
➣
➣
Divide by minus sign,
➣
➣
➣
➣
➣
➣
➣
As per assumption, y = breadth of the rectangle.
•°• y = -12 is not acceptable.
Substitute, y = 8 in equation 1,
➣
➣
➣
➣
Step-by-step explanation:
You use the formal y-y1=m(x-x1) to solve this and you plug in the #s so 2 and -4 will be x1 and y1 and 1/2 will be plunges is as m
Answer:
2.43675e+17
Step-by-step explanation:
sorry used calculator.
but still hope that this is correct.
Expand to get 35x^3+49x^2-20x-28