Simplify 5+10−2^3 <br> thanks in advance

Suppose three players go on multiple rounds of kart race. In each round, every player has a winning probability of 1/3, independ

zepelin [54]

Answer:

a) 0.3246

b) 0.0043

Step-by-step explanation:

For player 1 ; Probability of winning = P(W) = 1/3

Probability of loosing; P(winning) + P( Loosing) = 1

P(L) = 1 - 1/3 = 2/3

a) To find Find P(N <= 10) = P(2)+P(3)+P(4)+P(5)+P(6)+P(7)+P(8)+P(9)+P(10)

= (1/3)^2 + (1/3)^2 x 2/3 + (1/3)^2 x (2/3)^2 + (1/3)^2x (2/3)^3 + (1/3)^2 x (2/3)^4

X (1/3)^2 x (2/3)^5 + (1/3)^2 x (2/3)^6 + (1/3)^2 x (2/3)^7 + (1/3)^2 x (2/3)^8

= 0.3246

b) Find P(N = 10) = (1/3)^2 x (2/3)^8 = 0.0043

7 0

3 years ago

Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,

Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁, of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

$Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times (720-576)\times (720 - 672)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times 144 \times 48}$ = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

$Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}$

The semi-perimeter, s₂, of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

$Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times (690 -228)\times (690 - 480)}$

$Area\, of \, \Delta ACD = \sqrt{690 \times 18\times 462\times 210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2$

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0

3 years ago

What is 23,356.4739 rounded to the nearest whole number

nikitadnepr [17]

23,356 the answer rounded to nearest whole number

3 0

3 years ago

Read 2 more answers

Use the following triangle to find Sec theta.

makkiz [27]

Answer:

$\frac{\sqrt{41}}{4}$

Step-by-step explanation:

sec(theta) is defined as: $sec(\theta)=\frac{1}{cos(\theta)} = \frac{hypotenuse}{adjacent}$

In the diagram you provided the hypotenuse of the triangle is sqrt(41) and the opposite side is 5, using these two sides, we can solve for the adjacent side by using the Pythagorean Theorem: $a^2+b^2=c^2$

So this gives us the equation where a=adjacent side:

$a^2+5^2=\sqrt{41}^2$

$a^2+25=41$

Subtract 25 from both sides

$a^2=16$

Take the square root of both sides

$a=4$

So now plug this into the definition of sec(theta) and you get: $\frac{\sqrt{41}}{4}$ . This is in most simplified form since 41, has no factors besides 41 and 1.

7 0

2 years ago

Melody has 98 stickers. She gives 2/7 of them to her sister and 3/5 of the remainder to her brother. If she wants to increase he

anyanavicka [17]

Melody must buy 168 more stickers.

5 0

3 years ago

Read 2 more answers

Simplify 5+10−2^3 thanks in advance