Area of the electronic board is 9000 cm2
Step-by-step explanation:
Write ratios to represent the unknown actual length and width of the display to the scale length and width of the display.
The Electronic board always seems like a rectangular shape
Length= scale÷Actual = 5/36 = 5×36 = 180cm
![Length= scale÷Actual = 5/36 = 5×36 = 180cm](https://tex.z-dn.net/?f=Length%3D%20scale%C3%B7Actual%20%3D%205%2F36%20%3D%205%C3%9736%20%3D%20180cm)
Width=scale÷Actual = 1/50 = 1×50 = 50cm
![Width=scale÷Actual = 1/50 = 1×50 = 50cm](https://tex.z-dn.net/?f=Width%3Dscale%C3%B7Actual%20%3D%201%2F50%20%3D%201%C3%9750%20%3D%2050cm)
Area of Rectangle = legnth × width
= 180cm × 50cm = 9000 cm2
![= 180cm × 50cm = 9000 cm2](https://tex.z-dn.net/?f=%3D%20180cm%20%20%C3%97%2050cm%20%3D%209000%20cm2)
Area of the electronic board is 9000 cm2
Answer: u got a course hero account ?
Step-by-step explanation:
Answer: 2.09
Step-by-step explanation:
Answer:
2.6
Step-by-step explanation:
by similar property
![HJ=\frac{JI\times EG}{GF}\\x+16=\frac{31\times 36}{60}\\x+16=18.6\\x=2.6](https://tex.z-dn.net/?f=HJ%3D%5Cfrac%7BJI%5Ctimes%20EG%7D%7BGF%7D%3C%2Fp%3E%3Cp%3E%5C%5Cx%2B16%3D%5Cfrac%7B31%5Ctimes%2036%7D%7B60%7D%3C%2Fp%3E%3Cp%3E%5C%5Cx%2B16%3D18.6%3C%2Fp%3E%3Cp%3E%5C%5Cx%3D2.6)