Answer + Step-by-step explanation:
the inequality by finding the boundary line, then shading the appropriate area.
y > − 5/2x − 5
(anything in shaded region)
Answer:
![\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EExponential%20Rules%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5Dx%5E%7Ba%7D%20%2B%20x%5E%7Bb%7D%20%3D%20x%5E%7Ba%20%2B%20b%7D)
![\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} } = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5Bb%5D%7Bx%5E%7Ba%7D%20%7D%20%3Dx%5E%7B%5Cfrac%7Ba%7D%7Bb%7D%20%7D%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EOriginal%20Equation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%20%20%3D%20x%5E%7B%5Cfrac%7B10%7D%7B3%7D%20%7D%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EAnswer%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3EConvert%20the%20cubed%20root%20to%20a%20power.%20Cubed%20root%20%3D%20%5Btex%5D%5Cfrac%7B1%7D%7B3%7D)

Convert them, so they have a common denominator - 


[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]
156/12 = 12 * 13/12 = 13 :D
Answer:
Step-by-step explanation
Perimeter of a rectangle =2(length +breadth)
90m = 2{(36x+2) + (2(x+2)}
Opening the inner brackets,
90 = 2{36x +2+2x +4}
90 = 2{38x +6}
Open the brackets
90 = 76x + 12
Collect like terms
90 - 12 = 76x
78=76x
Divide 78 by the coefficient of x
x = 78÷76
x =1.03m (2d.p)
Substitute the value of x into the expressions for the two sides of the rectangle
36x+2 =(36×1.03) +2= 37.08+2=39.08m
2(x+2)= 2(1.03+2)= 2(3.03) =2×3.03= 6.06m
The approximate values of the two sides of d rectangular field are 39.08m and 6.06m