Answer: this one is confusing
Step-by-step explanation:
There are a number of ways this can be done. One that is fairly simple is as follows.
Triangle ABC has base AC = 9 and height B to AC of 3 (found by counting squares). Thus its area is ∆ABC = (1/2)·9·3 = 13.5 square units.
Triangle ACF has base AC = 9 and height F to AC of 3, so will have the same area as triangle ABC, 13.5 square units.
Trapezoid CDEF has base CD of 6, base EF of 4 and height EF to CD of 6 (found by counting squares). Thus its area is CDEF = (1/2)(6 + 4)(6) = 30.
The total area of the entire figure is then
... ∆ABC + ∆ACF + CDEF = 13.5 + 13.5 + 30 = 57 square units.
There are a total of 10 + 4 = 14 kg of syrup.
4 out of the 14 kg are sugar so the percentage is:
4/14 = 28.6%
Edit: The answer is correct. I don’t know why it was flagged as incorrect.
The total amount of ingredients in the syrup is 14 kg. Of the 14 kg, 4 kg is composed of sugar. So, 4 kg of sugar divided by the 14 kg of total weight will give you the percentage of sugar.
4/14 = 0.285714285714286
With an additional significant figure, the answer is 28.57%
Answer:
X=^49
Step-by-step explanation:
10. angle APB = (1/2) arc AB
108 = (1/2) arc AB
multiply both sides by 2 to clear the fraction
216 = arc AB
11. Area of regular Octagon s = 5 in
A = (P * apothem)/2 => => If you divide the octagon into 8 triangles, the apothem is the perpendicular height of the triangle.
A = (5 * 8 * 6)/2
A = 120 in^2
Area of regular Hexagon s = 5 in
A = (5 * 6 * 4.3)/2
A = 129 in^2
