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3 years ago

9

Suppose that from a group of 9 men, 1 will be randomly chosen for a dangerous assignment, and suppose that the chosen man will b

e killed during the assignment with a probability of 1/6. If Mark is one of the 9 men, what is the probability that he will be chosen for the assignment and killed during the assignment

1 answer:

tangare [24]3 years ago

8 0

Answer:

1/54

Step-by-step explanation:

1/9 x 1/6

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If XZ = 46 and wr= 21, find wx

Neporo4naja [7]

Answer:

966/zr.

Step-by-step explanation:

We are given that xz = 46 and wr = 21.

Therefore w = 21/r and x = 46/z.

Therefore wx = (21*46)/ zr

= 966/zr.

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Which example illustrates the associative property of addition for polynomials? [(2x2 + 5x) + (4x2 – 4x)] + 5x3 = (2x2 + 5x) + [

sertanlavr [38]

Answer:

[(2x2 + 5x) + (4x2 – 4x)] + 5x3 =

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A rectangular garden of area 456 square feet is to be surrounded on three sides by a brick wall costing $ 12 per foot and on one

solniwko [45]

Answer:

$l=2\sqrt{114}feet$ $b=2\sqrt{114}feet$ $\left ( l,b \right )=(21.3541,21.3541)$

Step-by-step explanation:

Given,

Area of garden=456 square feet

Brick wall cost three sides $=\$ 12$ per foot

fencing cost of one side $=\$ 7$ per foot

Let length and breadth of rectangular field is (l,b) feet

For minimizing the cost of material perimeter of garden should be minimum and area of garden is more.

Perimeter of garden $=2\left ( l+b \right )=k$

$l+b=k/2$

$l=k/2-b$

A= $l\times b=456$

A= $\left ( k/2-b \right )b=456$

Differentiating the equation to find maximum area

$\frac{d}{db}(\left ( k/2-b \right )b)=\frac{\partial 456}{\partial b}$

$k/2-2b=0$

$k=4b$

$l=4b/2-b$

$l=b$

To find $maxima$ again differentiating

$\frac{\partial A^2 }{\partial b^2}=\frac{\partial \left ( k/2-2b \right )}{\partial b}$

$\frac{\partial A^2 }{\partial b^2}$

The area is maximum when l=b

and perimeter is minimum

$l\times b=456$

$b^{2}=456$

$b=2\sqrt{114}feet$

$l=2\sqrt{114}feet$

Cost material

$=2\sqrt{114}\times 3\times 12+2\sqrt{114}\times 7$

$=72\sqrt{114}+14\sqrt{114}$

$=\$ 86\sqrt{114}$

$=\$ 918.22873$

Dimension of rectangular garden

$\left ( l,b \right )=(21.3541,21.3541)$

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3 years ago

dezoksy [38]

Using cosine rule,
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x^2=4.5^2+5.7^2-(2x4.5x5.7xcos 155)
x^2=99.2336
x=root over 99.2336
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