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Karolina [17]
3 years ago
9

Suppose that from a group of 9 men, 1 will be randomly chosen for a dangerous assignment, and suppose that the chosen man will b

e killed during the assignment with a probability of 1/6. If Mark is one of the 9 men, what is the probability that he will be chosen for the assignment and killed during the assignment
Mathematics
1 answer:
tangare [24]3 years ago
8 0

Answer:

1/54

Step-by-step explanation:

1/9 x 1/6

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Word problem:
Dahasolnce [82]

Step-by-step explanation:

=2* ( l+b )

=2* ( 11.37+9.245 )

=2* 20.595

=41.19

4 0
3 years ago
Average Daily Temperature in August
timurjin [86]

Answer:

The range for the average low temperatures for the states listed in the chart is B) 24.

Step-by-step explanation:

Low temperatures are:

56, 55, 65, 64, 55, 44, 54, 55, 68

First we put them in order from least to greatest

44, 54, 55, 55, 55, 56, 64, 65, 68

Range is maximum - minimum

68 is maximum and 44 is minimum

68 - 44 =

24

Hope this helps you! (:

-Hamilton1757

6 0
3 years ago
12 yd<br> 4 yd<br> 7 yd<br> 7yd<br> 4yd<br> 4 yd<br> 4 yd<br> 4 yd<br> what is the area
N76 [4]
I think the answer to it is 2,688
6 0
3 years ago
Describe how both the Rational Root Theorem and Descartes’ Rules of Signs help you to find the zeros of a polynomial? Give me an
MrRa [10]

Answer:

Step-by-step explanation:

Rational Root Theorem: If the polynomial

P(x) = a n x n + a n – 1 x n – 1 + ... + a 2 x 2 + a 1 x + a 0

has any rational roots, then they must be of the form of (factors of a0/factors of an).

Example: F(x) = 4x² + 5x +2

If this polynomial has any rational roots, then they must be (factors of 2)/(factors of 4), so (±1, ±2)/(±1, ±2, ±4). So if this polynomial has any rational roots, they must be either: ±1, ±1/2, ±1/4, or ±2. Notice that this polynomial doesn't have to have any rational roots, but if it does, then the roots must fit the Rational Root Theorem.

Descartes' Rules of Signs:

a). In a polynomial, how many time the sign changes is how many positive roots the polynomial will have.

Example: 5x³ + 6x² - 2x - 1

In this expression, the sign only changed once, between 6x² and 2x, so it will only have one positive root.

Example 2: 6x³ - 4x² + x - 6

In this expression, the sign changed 3 times (remember there is a invisible "+" sign before the 6x³), so it will have 3 positive roots.

b). In a polynomial, if you plug in "-x" for all "x", then how many times the new polynomial changes sign is how many negative roots the old polynomial have.

Example: 5x³ + 6x² - 2x - 1.

If we plug in "-x" for all "x", then we get 5(-x)³ + 6(-x)² - 2(-x) -1, which simplifies to -5x³ + 6x² + 2x -1. In this new expression, the sign changed twice, so we have two negative roots for the expression. Notice how we got one positive root the first time and two negative roots the second time, and 1 + 2 = 3. The Fundamental Theorem of Algebra states that for a nth degree polynomial, it will have n complex roots. The polynomial we worked with was a 3rd degree polynomial, and we got 1 + 2 = 3 roots in the end.

4 0
3 years ago
The point-slope form of the equation of a line that passes through points (8,4) and (0, 2) is y-
Oksi-84 [34.3K]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

While the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It's the slope

(x_ {0}, y_ {0}):It is a point through which the line passes

In this case we have a line through:

(8,4) and (0,2)

Therefore, its slope is:

m = \frac {2-4} {0-8} = \frac {-2} {- 8} = \frac {1} {4}

Its point-slope equation is:

y-4 = \frac {1} {4} (x-8)

Then, we manipulate the expression to find the equation of the slope-intersection form:

y-4 = \frac {1} {4} x- \frac {8} {4}\\y-4 = \frac {1} {4} x-2\\y = \frac {1} {4} x-2 + 4\\y = \frac {1} {4} x + 2

Therefore, the cut-off point with the y-axis is b = 2

ANswer:

y = \frac {1} {4} x + 2

7 0
3 years ago
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