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2 years ago

REALLY need help with this problem

Mathematics

2 answers:

aalyn [17]2 years ago

8 0

I TOLD U THE ANSWER CHECK

ValentinkaMS [17]2 years ago

8 0

Answer:

175.9

Step-by-step explanation:

Pi * 8(Diameter) * 7(Height) = 175.9291886...

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You got $300 for Christmas. You want to buy a hoodie that cost $52, a pair of pants that were $45 and you need shoes. Write an i

masya89 [10]

Answer:

she at least has $203 to buy a pair of shoes.

Step-by-step explanation:

Total allowance for Christmas = $300

Cost of 1 hood = $52

Cost of 1 pair of pants = $45

Let the cost of a pair of shoes = $m

Now, Cost of 1 hoodie + 1 pants + 1 pair shoes = $300

or, $52 + $45 + m = $300

or, m = 300 - 97 = 203

or, m = $203

Hence, she at least has $203 to buy a pair of shoes.

6 0

4 years ago

Read 2 more answers

In the given figure, O is centre of the circle. Find the value of x and y?

jok3333 [9.3K]

Answer:

x=30 cm

y=24 cm

Step-by-step explanation:

y=24 cm

x=√(24²+18²)=√[6²(4²+3²)]=6√(16+9)=6√25=6×5=30 cm

4 0

2 years ago

Read 2 more answers

Please Help Meh

Kitty [74]

The answers B.) positive

7 0

3 years ago

X^2-8x+16=5 what are the solutions?

svp [43]

Hey!

The first step to solving this equation would be to subtract 5 from both sides of the equation.

Original Equation :
$x^{2}$ - 8x + 16 = 5

New Equation {Added Subtract 5 to Both Sides} :
$x^{2}$ - 8x + 16 - 5 = 5 - 5

Now we solve our new equation.

Old Equation :
$x^{2}$ - 8x + 16 - 5 = 5 - 5

Solution {Old Equation Solved} :
$x^{2}$ - 8x + 11 = 0

The next step would be to solve with the quadratic formula.

Quadratic Equation ( 1 ) :
$x = \frac{-(-8) + \sqrt{(-8)^{2} -4 * 1 * 11 } }{2*1}$

Quadratic Equation ( 1 ) {Solved} :
4 + $\sqrt{5}$

Quadratic Equation ( 2 ) :
$x = \frac{-(-8) - \sqrt{(-8)^{2}-4 *1*11 } }{2*1}$

Quadratic Equation ( 2 ) {Solved} :
4 - $\sqrt{5}$

So, our final solutions for the equation $x^{2}$ - 8x + 16 = 5 are...

x = 4 + $\sqrt{5}$

and 

x = 4 - $\sqrt{5}$

Hope this helps!

- Lindsey Frazier ♥

5 0

3 years ago

Problem number 7 trigonometry

Natasha_Volkova [10]

7) - 1

tan <BAD = BD / AD

BC = √(64 + 36)
BC = √100
BC = 10

now you can solve BD
BD/6 = 6/10
BD = 6*6 / 10
BD = 36/10
BD = 3.6

AD = √36 - 12.96
AD = √23.04
AD = 4.8

tan <BAD = BD / AD
tan <BAD = 3.6 / 4.8
tan <BAD = 0.75

7) - 2

cos <DAC + cos <DAB

as you know cos = Adj / Hypo

cos <DAC = AD/AC
cos <DAC = 4.8 / 8
cos <DAC = 0.6

cos <DAB = AD / AB
cos <DAB = 4.8/6
cos <DAB = 0.8

so
cos <DAC + cos <DAB = 0.6 + 0.8
cos <DAC + cos <DAB = 1.4

hope it helps

8 0

3 years ago