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2 years ago

Pls help me I’m struggling

Mathematics

1 answer:

Leni [432]2 years ago

8 0

Answer: Peter < 65

Step-by-step explanation: Peter has less than charlie so charlie is more than or/and equal to being solid line underneath or solid line on graph represented by ≥ 65 stays equal to 65 or more which is a<em> correct statement</em> for charlie as charlie cards are<em> increasing </em>at 65 and has 65 and Peter is shown as ≤ 65 but is slightly wrong as we were told in question that 'he has just started collecting' this means it has to be or certainly less than charlie has - Just in diagram is interpreted as a <em>dotted line on graph coordinates</em><em> </em>represented by < 65<em> instead IS LESS THAN 65</em> would be correct way to interprete inequality of<em> Peters relationship value </em>to that of charlie given amount

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Plz, help ASAP!!!!!!!!!!

Ulleksa [173]

The answer is x= 53 because of verticals angles

8 0

4 years ago

Read 2 more answers

What is the area of a regular hexagon with a distance from its center to a vertex of 1 cm? (Hint: A regular hexagon can be divid

devlian [24]

<h3>Answer:</h3><h3>Exact area = $\frac{3}{2}\sqrt{3}$ square cm</h3><h3>Approximate area = 2.598 square cm</h3>

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Work Shown:

s = side length of equilateral triangle = 1 cm

A = area of equilateral triangle with side length 's'

$A = \frac{\sqrt{3}}{4}*s^2$

$A = \frac{\sqrt{3}}{4}*1^2$

$A = \frac{\sqrt{3}}{4}$

This is just one of the 6 equilateral triangles (see diagram below)

Multiply by 6 to get the area of all 6 equilateral triangles, or the entire hexagonal area

$6*A = 6*\frac{\sqrt{3}}{4}$

$6A = \frac{3\sqrt{3}}{2}$

$6A \approx 2.598$

4 0

3 years ago

What is the scale factor in the dilation?

Bumek [7]

The scale factor of the given dilation is 3.

Step-by-step explanation:

Step 1:

In order to determine the scale factor, we divide the measurement after scaling by the same measurement before scaling.

In the given graph, the preimage has a length of 3 units while the image has a length of 9 units.

Step 2:

So here the measurement after scaling is the length of the image which is 9 units and the measurement before scaling is the preimages length of 3 units.

The scale factor $=\frac{9}{3} = 3.$

So the scale factor is the third option 3.

8 0

3 years ago

Solve for s.<br> 8 – 4s = 8 +13

jarptica [38.1K]

Answer:

$-\frac{13}{4}$

Step-by-step explanation:

8 - 4s = 8 + 13

8 - 4s = 21

4s = 8 - 21

4s = - 13

s = -13/4

7 0

3 years ago

Two new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes. Drug

babymother [125]

Answer:

The total number of ways of assignment is 314,790,828,599,338,321,972,833,000.

Step-by-step explanation:

In mathematics, the procedure to select <em>k</em> items from <em>n</em> distinct items, without replacement, is known as combinations.

The formula to compute the combinations of <em>k</em> items from <em>n</em> is given by the formula:

${n\choose k}=\frac{n!}{k!(n-k)!}$

In this case we need to determine the number of ways in which the drugs are assigned to each mouse.

It is provided that new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes.

Drug A is to be given to 22 mice.

Compute the number of ways to assign drug A to 22 mice as follows:

${60\choose 22}=\frac{60!}{22!(60-22)!}\\\\=\frac{60!}{22!\times 38!}\\\\=14154280149473100$

Now the remaining number if mice are: 60 - 22 = 38.

Compute the number of ways to assign drug B to 22 mice as follows:

${38\choose 22}=\frac{38!}{38!(38-22)!}\\\\=\frac{38!}{22!\times 16!}\\\\=22239974430$

Now the remaining number if mice are: 38 - 22 = 16.

Compute the number of ways to assign no drug to 16 mice as follows:

${16\choose 16}=\frac{16!}{16!(16-16)!}\\\\=1$

The total number of ways of assignment is:

$N = {60\choose 22}\times {38\choose 22}\times {16\choose 16}\\\\=14154280149473100\times 22239974430\times 1\\\\=314,790,828,599,338,321,972,833,000$

Thus, the total number of ways of assignment is 314,790,828,599,338,321,972,833,000.

8 0

3 years ago