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Pavlova-9 [17]
2 years ago
14

Why is root 3 not 1.5

Mathematics
1 answer:
hram777 [196]2 years ago
8 0
Because 1.5 * 1.5 is 2.25 not 3 1.5 * 2 is 3
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Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of
GenaCL600 [577]

Close off the hemisphere S by attaching to it the disk D of radius 3 centered at the origin in the plane z=0. By the divergence theorem, we have

\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV

where R is the interior of the joined surfaces S\cup D.

Compute the divergence of \vec F:

\mathrm{div}\vec F(x,y,z)=\dfrac{\partial(xz^2)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial k}=z^2+y^2+x^2

Compute the integral of the divergence over R. Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\begin{cases}x^2+y^2+z^2=\rho^2\\\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi\end{cases}

So the volume integral is

\displaystyle\iiint_Rx^2+y^2+z^2\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{486\pi}5

From this we need to subtract the contribution of

\displaystyle\iint_D\vec F(x,y,z)\cdot\mathrm d\vec S

that is, the integral of \vec F over the disk, oriented downward. Since z=0 in D, we have

\vec F(x,y,0)=\dfrac{y^3}3\,\vec\jmath+y^2\,\vec k

Parameterize D by

\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

where 0\le u\le 3 and 0\le v\le2\pi. Take the normal vector to be

\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=-u\,\vec k

Then taking the dot product of \vec F with the normal vector gives

\vec F(x(u,v),y(u,v),0)\cdot(-u\,\vec k)=-y(u,v)^2u=-u^3\sin^2v

So the contribution of integrating \vec F over D is

\displaystyle\int_0^{2\pi}\int_0^3-u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac{81\pi}4

and the value of the integral we want is

(integral of divergence of <em>F</em>) - (integral over <em>D</em>) = integral over <em>S</em>

==>  486π/5 - (-81π/4) = 2349π/20

5 0
3 years ago
The function y = 5x is graphed in the coordinate plane. Which point will not be on the line?
Mademuasel [1]
I think your answer is A. (0,5)
Hope this helps!! Have a great day!! :)))
6 0
3 years ago
Read 2 more answers
For question 3, use the Pythagorean Theorem.
Juliette [100K]

Step-by-step explanation:

can't really use the Pythagorean because you don't know this is a right triangle.

use the fact that they are similar

so

3/6 = x/12 where x is FE

cross multiply

6x = 36 therefore FE = 6

then 6/12 = y/9 where y is FD

cross multiply

12y = 54 = 54/12 therefore FD = 4.5

3 0
2 years ago
Ella has a collection of vintage action figures that is worth $430. If the collection
valina [46]

The equation representing the value of the collection after 7 years is  value of collection = 430 + (0.04 * 430 )* 7 or value of collection = $550.4

<h3>What is an Equation ?</h3>

An equation is a mathematical statement , where the algebraic expression is equated to another algebraic expression.

It is given that

Ella has a collection of vintage action figures that is worth $430.

collection

appreciates at a rate of 4% per year

equation representing the value of the collection after 7 years is

value of collection = 430 + (0.04 * 430 )* t

value of collection = 430 + (0.04 * 430 )* 7

= $550.4

Therefore the equation representing the value of the collection after 7 years is  value of collection = 430 + (0.04 * 430 )* 7 or value of collection = $550.4

To know more about Equation

brainly.com/question/2263981

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4 0
1 year ago
10 POINTS <br><br> Could someone please answer these questions please
Natasha_Volkova [10]

Answer:

dont lie, thats only 5 points

5 0
3 years ago
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