Question

If the sides of a triangle are AB = 4x + 25, BC = 3x - 2, and AC = 9x - 5, determine the range of possible

Answer 1

The range of the possible values of x is:

x  >  4

For the given triangle:

AB = 4x + 25

BC = 3x - 2

AC = 9x - 5

The sum of two of the sides of the triangle should be greater than the length of the third side

That is:

AC  +  BC   >  AB

9x - 5  +  3x  -  2  >  4x + 25

12x - 7  >  4x  +  25

Collect like terms

12x  -  4x  >  25  +  7

8x  >  32

x   >  32/8

x  >  4

Therefore, the range of the possible values of x is:

x  >  4

Learn more triangle theorems here: brainly.com/question/2102943