Question

A bag contains 10 balls of which 6 are red and the rest white and blue of equal numbers. If a ball is picked at random, find the probability that it is either white or red.

Answer 1

Answer:

$\frac{4}{5}$

Step-by-step explanation:

Let $w$ = number of white balls, $b$ = number of blue balls

6 + $w$ + $b$ = 10

$w$ + $b$ = 4

$\because$ $w$ = $b$

$\therefore$ $w$ + $b$ =

$w$  = $2$

$P$($r$∪$w$) = $P(r) + P(w) - P(r$∩$w)$

= $\frac{6}{10} + \frac{2}{10} - \frac{0}{10}$

= $\frac{8}{10}$

= $\frac{4}{5}$

$\therefore$ The probability of picking either a red or white ball is $\frac{4}{5}$  

Hope this helps :)

Answer 2

Answer:

Since each ball has an equal chance of being drawn: 16 p = 1, or ... You can either apply the first equation to find that. B = 1 - R = 3/8 ... A box contains 5 white, 6 red, and 4 black balls of identical size. If 3 balls are ... What is the probability of getting 2 red balls if we pick 3 balls from the bag randomly

Step-by-step explanation: