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Lyrx [107]
3 years ago
12

The reaction below is at dynamic equilibrium. Upper N subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper

N upper H subscript 3 (g). Which statement is true for the equilibrium system? The concentration of NH3 is greater than the concentration of N2. The concentration of NH3 equals the concentration of N2. The rate of the forward reaction equals the rate of the reverse reaction. The rate of the forward reaction is greater than the rate of the reverse reaction.
Chemistry
2 answers:
Helen [10]3 years ago
5 0

Answer:

C

Explanation:

edg

Len [333]3 years ago
3 0

For the reaction below at dynamic equilibrium, it is true that the rate of the forward reaction equals the rate of the reverse reaction.

Let's consider the following reaction at equilibrium.

N₂(g) + 3 H₂(g) = 2 NH₃(g)

<h3>What is the chemical equilibrium?</h3>

Is a state in which the concentrations of reactants and products are constant and the forward reaction rate and constant reaction rate are equal.

<h3>What is the equilibrium constant?</h3>

The equilibrium constant (K) is the ratio of the concentrations of the products to the concentrations of the reactants, all raised to their stoichiometric coefficients.

Let's consider which statement is true for the equilibrium system.

  • The concentration of NH₃ is greater than the concentration of N₂. FALSE. There is not enough information to confirm this, we would need to know the value of K.
  • The concentration of NH₃ equals the concentration of N₂. FALSE. There is not enough information to confirm this, we would need to know the value of K.
  • The rate of the forward reaction equals the rate of the reverse reaction. TRUE. This is always true for a reaction at equilibrium.
  • The rate of the forward reaction is greater than the rate of the reverse reaction. FALSE. At equilibrium, both rates are equal.

For the reaction below at dynamic equilibrium, it is true that the rate of the forward reaction equals the rate of the reverse reaction.

Learn more about chemical equilibrium here: brainly.com/question/5081082

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Answer : The enthalpy change for converting 1 mole of ice at -25.0^oC to water at 90^oC is, 7.712 KJ

Solution :

Process involved in the calculation of enthalpy change :

(1):ice(-25^oC)\rightarrow ice(0^oC)\\\\(2):ice(0^oC)\rightarrow water(0^oC)\\\\(3):water(0^oC)\rightarrow water(90^oC)

Now we have to calculate the enthalpy change.

\Delta H=[m\times c_{ice}\times (T_2-T_1)]+\Delta H_{fusion}+[m\times c_{water}\times (T_3-T_2)]

where,

\Delta H = enthalpy change

m = mass of water = 1mole\times 18g/mole=18g

c_{ice} = specific heat of ice = 2.09 J/gk

c_{water} = specific heat of water = 4.18 J/gk

\Delta H_{fusion} = enthalpy change for fusion = 6.01 KJ/mole = 0.00601 J/mole

conversion : 0^oC=273k

T_1 = initial temperature of ice = 0^oC=273k

T_2 = final temperature of ice = -25^oC=273+(-25)=248k

T_3 = initial temperature of water = 0^oC=273k

T_4 = final temperature of water = 90^oC=273+90=363k

Now put all the given values in the above expression, we get

\Delta H=[18g\times 2.09J/gK\times (273-248)k]+0.00601J+[18g\times 4.18J/gK\times (363-273)k]

\Delta H=7712.106J=7.712KJ     (1 KJ = 1000 J)

Therefore, the enthalpy change for converting 1 mole of ice at -25.0^oC to water at 90^oC is, 7.712 KJ

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Read 2 more answers
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AURORKA [14]

<u>a) Answer: </u>

<em>Number of molecules in 1 mole</em>

<u>Explanation:</u>

a) Whether we take any of the substance among all three of the given substances they will have the same number of molecules in 1 mole of the substance is considered and the value for this will be 6.023 x 10^23

<u>b)  Answer: </u>

<em>In the given question </em><em>mass of the substance</em><em> which is </em><em>greatest</em><em> is asked for </em><em>one mole</em><em> and we also know that </em><em>mass of one mole is given by molar mass.  </em>

<u>Explanation:</u>

b) It is known that 31.98g/mol is the molar mass for oxygen which is greater than that of hydrogen while fluorine has a molar mass of 38.0 g/mol which on comparison shows that, it is the highest amongst all three.

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