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elixir [45]
2 years ago
14

The activation energy of an endothermic reaction _____.

Chemistry
2 answers:
amm18122 years ago
8 0

Answer:

must be greater than the required ΔH

Explanation:

The activation energy is the minimum extra amount of energy required by reactant molecules to undergo a reaction.

For both exothermic and endothermic reactions we need activation energy.

Enthalpy is the energy difference between products and reactants.

For endothermic reactions, enthalpy is positive as the energy of products is more than the energy of reactants.

As activation energy will be greater than the energy of both the reactants and products, so it must be greater than the enthalpy of reaction.

Explanation:

Anon25 [30]2 years ago
3 0
Endothermic reactions are reactions that require heat in the course of the process. The heat of reaction in this case is positive which means the energy of the products is greater than the energy of the reactants. In this case, the answer to this problem would have to be <span>1. must be greater than the required ΔH </span>
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All of the following are equal to Avogadro's number EXCEPT ____. a. the number of atoms of bromine in 1 mol Br2 b. the number of
Colt1911 [192]

All the following are equal to Avogadro's number EXCEPT a. the number of atoms of bromine in 1 mol Br₂.

1 mol Br₂ contains Avogadro’s number of molecules of Br₂.

However, each molecule contains two atoms of Br, so there are

<em>2 × Avogadro’s number of Br atoms </em>in 1 mol Br₂.

8 0
2 years ago
3% Hydrogen Peroxide has an oral LD50 of 900 mg/kg. Acetic Acid has an oral LD50 of 3310 mg/kg. Which one is more hazardous to c
Lina20 [59]
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4 0
3 years ago
In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for
inessss [21]

Answer:

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

Cu^{2+}(aq)+Fe(s)\rightarrow Cu(s)+Fe^{2+}(aq)

Reduction at cathode :

Cu^+(aq)+2e^-\rightarrow Cu(s)

Reduction potential of  Cu^{2+} to Cu=E^o_{1}=0.34 V

Oxidation at anode:

Fe(s)\rightarrow Fe^{2+}(aq)+2e^-

Reduction potential of  Fe^{2+} to Fe=E^o_{2}=-0.44 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Putting values in above equation, we get:

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The standard cell potential of the reaction is 0.78 Volts.

3 0
3 years ago
These are elements that
agasfer [191]

Answer:

metals are those element that have luster,malleable, ductile good conductors of heat and électricity, must have high melting and boiling points, and lose electrons in chemical reactions.

6 0
2 years ago
3.0 x 108 m/s is the
Veseljchak [2.6K]

Answer:

Speed of light

Explanation:

The value 3.0 x 10⁸m/s is taken as the speed of light.

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  • The speed of electromagnetic radiations in free space is also taken as the speed of light.
4 0
3 years ago
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