Answer:
1 is ur answer
Explanation:
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Answer:
Q = 8.8 kJ
Explanation:
Step 1: Data given
The specific heat of a solution = 4.18 J/g°C
Volume = 296 mL
Density = 1.03 g/mL
The temperature increases with 6.9 °C
Step 2: Calculate the mass of the solution
mass = density * volume
mass = 1.03 g/mL * 296 mL
mass = 304.88 grams
Step 3: Calculate the heat
Q = m*c*ΔT
⇒ with Q = the heat in Joules = TO BE DETERMINED
⇒ with m = the mass of the solution = 304.88 grams
⇒ with c = the specific heat of the solution = 4.18 J/g°C
⇒ with ΔT = the change in temperature = 6.9 °C
Q = 304.88 g * 4.18 J/g°c * 6.9 °C
Q = 8793.3 J = 8.8 kJ
Q = 8.8 kJ
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Yes, it is a special case of enthalpy of neutralization.
The enthalpy of neutralization (ΔHn) is the change in enthalpy that occurs when one equivalent of an acid and one equivalent of a base undergo a neutralization reaction to form water and a salt.
The standard enthalpy change of neutralization is the enthalpy change when solutions of an acid and an alkali react together under standard conditions to produce 1 mole of water.
Explanation:
1. photosynthesis
2. Nucleus. The nucleus is the largest and most significant living organelle of the cell. ... Hence it is called brain or control centre of the cell.
3.Cytoplasm
Cells require a thick jelly-like substance that holds organelles in place inside the cell. This substance is known. Cytoplasm. Turgor pressure can help plants move.
4.Chloroplasts absorbing solar energy for cellular activities.
5.cell membrane
6.a.cell wall
b.chloroplast
c.large vacuole
