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guajiro [1.7K]
2 years ago
7

Jonita determined that the distance between her apartment and the nearest hospital was more than 1,600 meters but less than 1,90

0 meters. Which of the following could be a reasonable estimate for
the distance between her house and the hospital?

O 1.7 x 102 meters
O 1.8 x 103 meters
O 1.7 x 10-3 meters
O 1.8 x 10-2 meters
Mathematics
1 answer:
Bess [88]2 years ago
7 0

Answer: 1.8 x 103 meters

Step-by-step explanation:

The average of the two extremes is 1,700 meters.  This would be 1.7x10^3 in scientific notation.  None of the four options include this number.  But three stand out as total losers.  We can convert the answer options to see the difference:

O 1.7 x 102 meters  =    170 meters      [Loser]

O 1.8 x 103 meters  =  1800 meters

O 1.7 x 10-3 meters =  0.0017 meters   [Loser]

O 1.8 x 10-2 meters =  0.018 meters     [Loser]

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a triangular sail has sides of 10 ft ,24ft,and 26ft .if the shortest side of a similar sail measures 6ft , what is the measure o
Katarina [22]

Answer:

15.6 ft

Step-by-step explanation:

Since the sails are similar then the ratios of corresponding sides are equal.

Comparing the shortest sides, that is

10 : 6 = 5 : 3

let the longest side be x, then using proportion

\frac{26}{5} = \frac{x}{3} ( cross- multiply )

5x = 78 ( divide both sides by 5 )

x = 15.6

The longest side is 15.6 ft

5 0
3 years ago
A person walks 1/4 mile in 1/8 hour what is there miles per hour
hammer [34]
1/4 miles in 1/8 hour
?mile in 1 hour
Step 1:
Cross Multiply
1×1/4=1/4
Step 2:
1/4÷1/8=2 miles. As a result,a person walks 2 miles in 1 hour. Hope it help!
5 0
3 years ago
I'm reasking a previous question to make it more clear. This is a Linear Equation that I must solve. It includes fractions (the
Ugo [173]

Assuming the equation is:

\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)


When fractions involve numeric denominators, the fractions can be removed by multiplying (both sides) by the LCM of the denominators.


Here the denominators are 2 and 10, hence the LCM is 10.


Multiply by 10 on both sides, not forgetting to distribute when multiplying on the right side:

10\frac{x}{2}-10\frac{10x-25}{10}=10*3(x+3)-10(x-14)

simplify, remember that there are always implied parentheses around numerators and denominators:

5x-(10x-25)=30(x+3)-10(x-14)

Now, distribute, i.e. remove parentheses and distribute:

5x-10x+25=30x+90-10x+140

Simplify

-5x+25=20x+230

transpose terms

25-230=20x+5x

solve

x=-205/25=-41/5


In this particular case, we can also take advantage of the term

(10x-25)/10=5(2x-5)/10=(2x-5)/2 which greatly simplifies the solution process, because the LCM will then be 2 instead of 10.

If we do that, the solution will be:

Multiply by 2 on both sides, not forgetting to distribute when multiplying on the right side:

\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)

simplify, remember that there are always implied parentheses around numerators and denominators:

2\frac{x}{2}-2\frac{2x-5}{2}=2*3(x+3)-2(x-14)

x-(2x-5)=6(x+3)-2(x-14)

Now, distribute, i.e. remove parentheses and distribute:

x-2x+5=6x+18-2x+28

Simplify

-x+5=4x+46

solve

5-46=4x+x

-41=5x

x=-41/5

with the same results.

7 0
3 years ago
Read 2 more answers
Suppose the test scores for a college entrance exam are normally distributed with a mean of 450 and a s. d. of 100. a. What is t
svet-max [94.6K]

Answer:

a) 68.26% probability that a student scores between 350 and 550

b) A score of 638(or higher).

c) The 60th percentile of test scores is 475.3.

d) The middle 30% of the test scores is between 411.5 and 488.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 450, \sigma = 100

a. What is the probability that a student scores between 350 and 550?

This is the pvalue of Z when X = 550 subtracted by the pvalue of Z when X = 350. So

X = 550

Z = \frac{X - \mu}{\sigma}

Z = \frac{550 - 450}{100}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 350

Z = \frac{X - \mu}{\sigma}

Z = \frac{350 - 450}{100}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a student scores between 350 and 550

b. If the upper 3% scholarship, what score must a student receive to get a scholarship?

100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So it is X when Z = 1.88

Z = \frac{X - \mu}{\sigma}

1.88 = \frac{X - 450}{100}

X - 450 = 1.88*100

X = 638

A score of 638(or higher).

c. Find the 60th percentile of the test scores.

X when Z has a pvalue of 0.60. So it is X when Z = 0.253

Z = \frac{X - \mu}{\sigma}

0.253 = \frac{X - 450}{100}

X - 450 = 0.253*100

X = 475.3

The 60th percentile of test scores is 475.3.

d. Find the middle 30% of the test scores.

50 - (30/2) = 35th percentile

50 + (30/2) = 65th percentile.

35th percentile:

X when Z has a pvalue of 0.35. So X when Z = -0.385.

Z = \frac{X - \mu}{\sigma}

-0.385 = \frac{X - 450}{100}

X - 450 = -0.385*100

X = 411.5

65th percentile:

X when Z has a pvalue of 0.35. So X when Z = 0.385.

Z = \frac{X - \mu}{\sigma}

0.385 = \frac{X - 450}{100}

X - 450 = 0.385*100

X = 488.5

The middle 30% of the test scores is between 411.5 and 488.5.

7 0
3 years ago
Is the result of Double 5 and add 1 the same as the result of Add 1 to 5; then double the result?
just olya [345]
B. Double 5 plus 1 equals 11 and add 1 to 5 doubled equals 12.
7 0
3 years ago
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